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Class 11 Physics Assignments

We have provided below free printable Class 11 Physics Assignments for Download in PDF. The Assignments have been designed based on the latest NCERT Book for Class 11 Physics . These Assignments for Grade 11 Physics cover all important topics which can come in your standard 11 tests and examinations. Free printable Assignments for CBSE Class 11 Physics , school and class assignments, and practice test papers have been designed by our highly experienced class 11 faculty. You can free download CBSE NCERT printable Assignments for Physics Class 11 with solutions and answers. All Assignments and test sheets have been prepared by expert teachers as per the latest Syllabus in Physics Class 11. Students can click on the links below and download all Pdf Assignments for Physics class 11 for free. All latest Kendriya Vidyalaya Class 11 Physics Assignments with Answers and test papers are given below.

Physics Class 11 Assignments Pdf Download

We have provided below the biggest collection of free CBSE NCERT KVS Assignments for Class 11 Physics . Students and teachers can download and save all free Physics assignments in Pdf for grade 11th. Our expert faculty have covered Class 11 important questions and answers for Physics as per the latest syllabus for the current academic year. All test papers and question banks for Class 11 Physics and CBSE Assignments for Physics Class 11 will be really helpful for standard 11th students to prepare for the class tests and school examinations. Class 11th students can easily free download in Pdf all printable practice worksheets given below.

Topicwise Assignments for Class 11 Physics Download in Pdf

Class 11 Physics Assignments

Advantages of Class 11 Physics Assignments

  • As we have the best and largest collection of Physics assignments for Grade 11, you will be able to easily get full list of solved important questions which can come in your examinations.
  • Students will be able to go through all important and critical topics given in your CBSE Physics textbooks for Class 11 .
  • All Physics assignments for Class 11 have been designed with answers. Students should solve them yourself and then compare with the solutions provided by us.
  • Class 11 Students studying in per CBSE, NCERT and KVS schools will be able to free download all Physics chapter wise worksheets and assignments for free in Pdf
  • Class 11 Physics question bank will help to improve subject understanding which will help to get better rank in exams

Frequently Asked Questions by Class 11 Physics students

At https://www.cbsencertsolutions.com, we have provided the biggest database of free assignments for Physics Class 11 which you can download in Pdf

We provide here Standard 11 Physics chapter-wise assignments which can be easily downloaded in Pdf format for free.

You can click on the links above and get assignments for Physics in Grade 11, all topic-wise question banks with solutions have been provided here. You can click on the links to download in Pdf.

We have provided here topic-wise Physics Grade 11 question banks, revision notes and questions for all difficult topics, and other study material.

We have provided the best collection of question bank and practice tests for Class 11 for all subjects. You can download them all and use them offline without the internet.

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assignment 3 4 physics class 11

  • Motion and Force

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Displacement

Define Displacement

Define velocity, define acceleration.

Acceleration

Velocity-Time Graph

Velocity Time Graph

Review equation of uniformly accelerated motion.

Review of Equations of Uniformly Accelerat

Review of Equations of uniformly Acceleration Motion

Newton's law of motion.

Newton's Law of Motion

Newton’s Law of Motion

Define momentum, define impulse, law of conservations of momentum.

Elastic and Inelastic Collision

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Force Due to Water Flow

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Momentum and explosive force.

Momentum & Explosive Force

Rocket Propulsion

Projectile Motion

Exercise Numerical no 3.1 to 3.3

Exercise numerical no 3.4 to 3.6, exercise numerical no 3.7 and 3.8, exercise numerical no 3.9 to 3.11, exercise numerical no 3.12 to 3.15, exercise question no 3.1 and 3.2.

Exercise Question

Exercise Question no 3.3 and 3.4

Exercise question no 3.5 and 3.6, exercise question no 3.7 and 3.8, exercise question no 3.9 to 3.12, exercise question no 3.13 and 3.14, physics chapter 3 exercise example no 3.1, physics chapter 3 exercise example no 3.2, physics chapter 3 exercise example no 3.3, physics chapter 3 exercise example no 3.4, exercise example 3.1, exercise example 3.2 and 3.3, exercise example 3.4 and 3.5, exercise example 3.6.

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11th Class Online Test

Class : 11th class, subject : physics, chapter : motion and force, topic : physics chapter 3 exercise example no 3 4.

  • Introduction First Year Physics
  • Measurements
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  • Work and Energy
  • Circular Motion
  • Fluid Dynamics
  • Oscillations
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NCERT Solutions for Class 11 Physics

assignment 3 4 physics class 11

NCERT Solutions for Class 11 Physics in Hindi and English Medium PDF format are available to download updated for new academic session 2024-25. CBSE Class 11 Physics NCERT Solutions are a set of comprehensive and detailed answers, explanations, and solutions for the exercises and problems presented in the Class 11 Physics textbook published by the National Council of Educational Research and Training (NCERT). These solutions are designed to help students understand and master the concepts covered in the Physics curriculum for Class 11 under the Central Board of Secondary Education (CBSE) in India. Get here Solutions of Exercises, Additional Exercises, Supplementary material and NCERT books. Class 11 Physics Chapter Wise NCERT Solutions Chapter 1. Units and Measurements Chapter 2. Motion in a Straight Line Chapter 3. Motion in a Plane Chapter 4. Laws of Motion Chapter 5. Work, Energy and Power Chapter 6. System of Particles and Rotational Motion Chapter 7. Gravitation Chapter 8. Mechanical Properties of Solids Chapter 9. Mechanical Properties of Fluids Chapter 10. Thermal Properties of Matter Chapter 11. Thermodynamics Chapter 12. Kinetic Theory Chapter 13. Oscillations Chapter 14. Waves The CBSE Class 11 Physics NCERT Solutions offer step-by-step explanations for the various types of questions and problems found in the textbook. These solutions cover a wide range of topics in physics, including mechanics, thermodynamics, waves, optics, electromagnetism, and more. By providing clear explanations, diagrams, graphs, and examples, these solutions aim to make complex physics concepts accessible and understandable to students.

Offline Apps based on latest NCERT Solutions for (+1) are available to download along with the answers given at the end of the book. Key features and benefits of CBSE Class 11 Physics NCERT Solutions are given here. The solutions help students develop a strong understanding of fundamental physics concepts, laying the foundation for advanced topics in Class 12 and beyond. Revision books, based on Latest CBSE Syllabus, for each chapter as well as notes of each chapter are available to download in PDF format. Chapter tests and assignments will be uploaded time to time. Class 11 Physics NCERT Solutions align with the CBSE curriculum, making them valuable study materials for exams, including school exams and board exams. If you are having any suggestion for the improvement, your are welcome. The improvement of the website and its contents are based on your suggestion and feedback.

The solutions include practice exercises that allow students to apply their knowledge and practice problem-solving skills. These follow a logical sequence, guiding students through the thought process required to solve different types of physics problems. Class 11 Physics  NCERT text book solutions  are given here to download in PDF. Extra study material covering the whole syllabus divided into 10 units will help the students in revising the complete course.  Unit 1  contains the material related to dimension and measurement,  Unit 2  is covering Kinematics,  Unit 3  covers the newton’s law of motion, similarly the  Unit 4 ,  Unit 5 ,   Unit 6 ,  Unit 7 ,  Unit 8 ,  Unit 9  and  Unit 10  covers the entire curriculum. Many physics concepts are explained using diagrams, graphs, and illustrations to enhance understanding. The solutions often include real-world examples that demonstrate the practical applications of physics concepts.

NCERT Book solutions are prepared by experienced educators and experts in the field. This ensures that the content is accurate, reliable, and follows the best pedagogical practices. Strong comprehension of Class 11 physics concepts facilitated by these solutions can help students prepare for various competitive entrance exams. CBSE Class 11 Physics NCERT Solutions are designed to be self-explanatory, making them suitable for self-study and independent learning. In essence, Class 11 Physics NCERT solutions play a crucial role in helping students lay a solid foundation in physics, providing them with the necessary skills and knowledge to excel in their studies and future pursuits.

Chapter Wise Study material for Class 11 Physics Unit 1 to 10

  • Class 11 Physics Study Material Unit 1
  • Class 11 Physics Study Material Unit 2
  • Class 11 Physics Study Material Unit 3
  • Class 11 Physics Study Material Unit 4
  • Class 11 Physics Study Material Unit 5
  • Class 11 Physics Study Material Unit 6
  • Class 11 Physics Study Material Unit 7
  • Class 11 Physics Study Material Unit 8
  • Class 11 Physics Study Material Unit 9
  • Class 11 Physics Study Material Unit 10

11th Physics solutions are prepared by subject matter experts, ensuring accuracy and quality in the explanations and solutions provided. Overall, CBSE Class 11 Physics NCERT Solutions serve as a valuable resource to help students master the subject, develop problem-solving skills, and prepare for exams and future academic pursuits in the field of physics or related disciplines.

Chapter Wise Revision Books for Class 11 Physics

  • Revision Book Chapter 1: Units and Measurements
  • Revision Book Chapter 2: Motion in a Straight Line
  • Revision Book Chapter 3: Motion in a Plane
  • Revision Book Chapter 4: Laws of Motion
  • Revision Book Chapter 5: Work, Energy and Power
  • Revision Book Chapter 6: System of Particles and Rotational Motion
  • Revision Book Chapter 7: Gravitation
  • Revision Book Chapter 8: Mechanical Properties of Solids
  • Revision Book Chapter 9: Mechanical Properties of Fluids
  • Revision Book Chapter 10: Thermal Properties of Matter
  • Revision Book Chapter 11: Thermodynamics
  • Revision Book Chapter 12: Kinetic Theory
  • Revision Book Chapter 13: Oscillations
  • Revision Book Chpater 14: Waves
  • Revision Books Solutions and Answers Part 1
  • Revision Books Solutions and Answers Part 2

The NCERT solutions for Class 11 Physics hold significant importance for students. Physics is a fundamental subject that forms the basis for many scientific and technical fields. Here’s why Class 11 Physics Tiwari Academy NCERT solutions are important. Class 11 Physics introduces students to essential concepts that lay the groundwork for more advanced topics in higher classes.

The work ‘Physics’ has originated from Greek work fusis, meaning nature. So, in physics we deal with nature and natural phenomena. We understand nature only through the study matter, energy and their interactions. The solutions provided in NCERT textbooks and their solutions align closely with the CBSE Class 11 Physics syllabus. As a result, studying these solutions thoroughly prepares students for their exams, including the board exams and competitive entrance exams.

Practice Test based on all Chapters of 11 Physics NCERT

  • 11th Physics Chapter 1 Test 1
  • 11th Physics Chapter 2 Test 1
  • 11th Physics Chapter 2 Test 2
  • 11th Physics Chapter 3 Test 1
  • 11th Physics Chapter 4 Test 1
  • 11th Physics Chapter 5 Test 1
  • 11th Physics Chapter 5 Test 2
  • 11th Physics Chapter 6 Test 1
  • 11th Physics Chapter 6 Test 2
  • 11th Physics Chapter 7 Test 1
  • 11th Physics Chapter 7 Test 2
  • 11th Physics Chapter 8 Test 1
  • 11th Physics Chapter 8 Test 2
  • 11th Physics Chapter 9 Test 1
  • 11th Physics Chapter 10 Test 1
  • 11th Physics Chapter 10 Test 2
  • 11th Physics Chapter 11 Test 1
  • 11th Physics Chapter 12 Test 1
  • 11th Physics Chapter 13 Test 1
  • 11th Physics Chapter 14 Test 1
  • 11th Physics Chapter 15 Test 1
  • 11th Physics Chapter 15 Test 2

Physics involves problem-solving and critical thinking. NCERT solutions include a variety of exercises that require students to apply concepts to solve problems. Practicing these problems hones their analytical and problem-solving skills. It often involves visual concepts, such as diagrams, graphs, and illustrations. NCERT solutions use these visual aids to explain concepts, making it easier for students to grasp abstract ideas.

Mechanics and properties of matter, Heat and thermodynamics, Sound or acoustics, Electricity and magnetism, Modern physics, Biophysics, Astrophysics, Geophysics, Nuclear physics , etc. Physics is based on mathematical equations and formulas. NCERT solutions break down these equations step by step, making it easier for students to understand how they are derived and applied.

1. Classical Mechanics: It explains the motion of particles which travel with velocities much less than that of light. 2. Theory of Relativity: It explains the in-variance in nature and also the motion of particles which travel with velocities close to that of light. 3. Thermodynamics: It is the theory of heat, temperature and conversion of heat into work and vice-versa. It also explains the behaviours of systems containing very large number of particles. NCERT solutions often include real-life examples that demonstrate the practical applications of physics concepts. This helps students relate theoretical concepts to the world around them.

4. Electromagnetism: It is theory of electricity, magnetism and the electromagnetic radiation including optics. 5. Quantum Mechanics: It explains the behaviours of atomic and subatomic systems of particles. According to Albert Einstein, Science is not just a collection of laws, a catalogue of unrelated facts. It is a creation of human mind with its freely invented ideas and concepts. About modern physics, he said, the reality created by modern physics is indeed, far removed from the reality of the early days. Many competitive entrance exams for engineering and other science-related fields include physics questions. Strong foundational knowledge gained from NCERT solutions can give students an advantage in such exams.

Class 1 Physics Chaperwise Revision Notes

  • Class 11 Physics Chapter 1 Revision Questions
  • Class 11 Physics Chapter 1 Revision Notes
  • Class 11 Physics Chapter 2 Revision Notes
  • Class 11 Physics Chapter 3 Revision Notes
  • Class 11 Physics Chapter 4 Revision Notes
  • Class 11 Physics Chapter 5 Revision Notes
  • Class 11 Physics Chapter 6 Revision Notes
  • Class 11 Physics Chapter 7 and 8 Revision Notes
  • Class 11 Physics Chapter 9 Revision Notes
  • Class 11 Physics Chapter 10 Revision Notes

The animate and ananimate – all objects are made up of matter and energy. Therefore, any type of study of an object is basically the study of some manifestation of matter and energy. The concepts learned in Class 11 Physics are built upon in Class 12 and higher education. Understanding Class 11 concepts thoroughly using NCERT solutions ensures a smooth transition to more advanced topics. The matter and energy is the subject of study of physics, hence the laws of physics are at work at the root of the all sciences. Therefore, it need not be surprising if some direct modification of the laws of physics appear to be underlying the human behaviour also. Due to these reasons physics has intimate relationship with all the sciences and hence it is called a fundamental science. Physics requires logical reasoning and critical analysis. By working through NCERT solutions, students develop logical thinking skills that are valuable in various academic and professional pursuits.

Class 11 Physics Chapterwise Assignments

  • Physics Mathematical Tools
  • 11 Physics Chapter 4 Assignment 1
  • 11 Physics Chapter 7 Assignment 1
  • 11 Physics Chapter 7 Assignment 2
  • 11 Physics Chapter 7 Assignment 3
  • 11 Physics Chapter 7 Assignment 4
  • 11 Physics Chapter 7 Assignment 5
  • 11 Physics Chapter 8 Assignment 1
  • 11 Physics Chapter 8 Assignment 2
  • 11 Physics Chapter 8 Assignment 3
  • 11 Physics Chapter 8 Assignment 4
  • 11 Physics Chapter 8 Assignment 5
  • 11 Physics Chapter 9 Assignment 1
  • 11 Physics Chapter 9 Assignment 2
  • 11 Physics Chapter 10 Assignment 1
  • 11 Physics Chapter 10 Assignment 2
  • 11 Physics Chapter 10 Assignment 3
  • 11 Physics Chapter 10 Assignment 4
  • 11 Physics Chapter 10 Assignment 5
  • 11 Physics Chapter 12 Assignment 1
  • 11 Physics Chapter 12 Assignment 2
  • 11 Physics Chapter 13 Assignment 1
  • 11 Physics Chapter 13 Assignment 2
  • 11 Physics Chapter 13 Assignment 3
  • 11 Physics Chapter 14 and 15 Assignment 1
  • 11 Physics Chapter 14 and 15 Assignment 2
  • 11 Physics Chapter 14 and 15 Assignment 3
  • 11 Physics Chapter 14 and 15 Assignment 4
  • 11 Physics Chapter 14 and 15 Assignment 5

NCERT solutions are designed to be self-explanatory. This makes them a great resource for self-study, enabling students to learn and revise concepts independently. Ask your doubts related to NIOS or CBSE Board and share your knowledge with your friends and other users through Discussion Forum . Download NCERT Solutions and CBSE Offline Apps based on latest NCERT Books. Class 11 Physics covers a wide range of topics, including mechanics, thermodynamics, waves, and more. NCERT textbook solutions provide a comprehensive understanding of these topics, helping students build a holistic view of the subject.

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  • NCERT 11 Physics

NCERT Solutions for Class 11 Physics

Download chapter-wise ncert solutions for class 11 physics.

NCERT Solutions for Class 11 Physics for all chapters can be accessed here by following the links provided below. The highly experienced subject matter experts have explained each and every minute concept in the best way possible to help students face the exam without fear. Physics is a subject which contains a lot of concepts and numerical problems. For this purpose, a thorough understanding of the concepts is necessary to solve the problems effortlessly. NCERT Solutions  is prepared in order to provide the students with authentic information completely based on the latest syllabus prescribed by the CBSE board.

From Class 11 Physics, students will study the various concepts which are important both from the exam and competitive exam perspective. The solutions provided here can be accessed by the students in online mode or can be downloaded as a PDF. Each chapter of NCERT Solutions for Class 11 Physics can be downloaded in a PDF format by clicking on the “Download PDF” button at the top of each chapter page given below.

NCERT Solutions for Class 11 Physics (Chapter-wise)

  • Chapter 1: Units and Measurements
  • Chapter 2: Motion in a Straight Line
  • Chapter 3: Motion in a Plane
  • Chapter 4: Laws of Motion
  • Chapter 5: Work, Energy, and Power
  • Chapter 6: System of Particles and Rotational Motion
  • Chapter 7: Gravitation
  • Chapter 8: Mechanical Properties of Solids
  • Chapter 9: Mechanical Properties of Fluids
  • Chapter 10: Thermal Properties of Matter
  • Chapter 11: Thermodynamics
  • Chapter 12: Kinetic Theory
  • Chapter 13: Oscillations
  • Chapter 14: Waves

The following chapters have been removed from the NCERT Class 11 Physics textbook 2023-24.

Physical World

Class 11 is an important stage in the life of a student because they are exposed to learning various new concepts. The solutions at BYJU’S not only helps them to understand it but also provides them with a basic knowledge of their applications in our daily life. So learning the chapters present in the NCERT textbook will help them to obtain a strong hold on the basic concepts. There are numerical problems and examples present in each chapter, which are explained in a step-wise manner to improve the problem-solving abilities of the students.

Download NCERT Solutions for Class 11 Physics to speed up the exam preparation.

NCERT Solutions Class 11 Physics

NCERT Solutions Class 11 Physics is an important study material which helps students to master the subject. Physics is a crucial subject from the exam perspective, which is difficult to master as it deals with various properties of nature and matter. It forms a strong base for students who wish to pursue higher levels of education in the field of Science. The solutions are planned out to aid the Class 11 students in achieving good marks in the exam. The expert teachers answer each and every question in an elaborate manner so that students do not miss any concept which is important for the exam. By regular practice using the NCERT Solutions, students will be able to know the right way to approach the questions which would appear in the exam.

NCERT Solutions Class 11 Physics Chapter Details and Exercises

Chapter 1: physical world.

In this chapter, we will be studying how things work and the reason behind it. Students will become more aware of the things surrounding them, the origin and the history of Science. They will also come across various aphorisms and their justification using Physics concepts in real life in this chapter. The concepts covered here are gravitational force , electromagnetic force, strong and weak nuclear force. The theories and observations done by various scientists and their conclusion is provided briefly here. You will gain more idea about the factors which are the reasons for the development of Science and Technology in our country. The existence of an electron is explained in this chapter in an elaborate manner to acquaint students with the basic conceptual knowledge.

Topics Covered in Class 11 Physics Chapter 1 Physical World

Physics: Scope and excitement; nature of physical laws; Physics, technology and society

Also, access the following resources for Class 11 Chapter 1 Physical World, at BYJU’S:

  • Physical World Class 11 Notes Chapter 1
  • Physics Revision Notes for Class 11 Chapter 1 Physical World
  • Physical World and Measurement MCQs
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 1 – Introduction

Chapter 2: Units and Measurements

With the senses like ears, eyes etc., scientists gather information and make observations. A few of them are like figuring out the colour and texture, while others would be complex where measurement is necessary. It is a basic concept in Science without which scientists will not be able to conduct any experiments. Students will learn about the units of physical quantities and the method to be followed to evaluate them. It will also provide a good idea of the errors which would occur while measuring things and significant figures.

Topics Covered in Class 11 Physics Chapter 2 Units and Measurements

Need for measurement: Units of measurement; systems of units; SI units, fundamental and derived units. Length, mass and time measurements; accuracy and precision of measuring instruments; errors in measurement; significant figures. Dimensions of physical quantities, dimensional analysis and its applications.

Also, access the following resources for Class 11 Chapter 2 Units and Measurements, at BYJU’S:

  • NCERT Exemplar Class 11 Physics Solutions for Chapter 2 – Units and Measurements
  • Chapter 2 – Units and Measurements
  • Class 11 Physics Units and Measurements Chapter 2 Notes

Chapter 3: Motion in a Straight Line

This chapter will cover essential topics like comparing objects as point object and the method of plotting graphs and finding the values based on them. The method plotting x-t motion graph can be learnt easily by using the NCERT Solutions from BYJU’S. The time taken by a biker, the speed of a car and the time taken by a bus to travel can be found effortlessly by referring to these solutions. Students will learn the difference between magnitude of displacement and the total length of the path covered. They will also study about the average speed, average velocity, instantaneous speed and velocity as per the CBSE guidelines.

Topics Covered in Class 11 Physics Chapter 3 Motion in a Straight Line

Frame of reference. Motion in a straight line: Position-time graph, speed and velocity. Uniform and non-uniform motion, average speed and instantaneous velocity. Uniformly accelerated motion, velocity-time and position-time graphs, relations for uniformly accelerated motion (graphical treatment). Elementary concepts of differentiation and integration for describing motion.

Also, access the following resources for Class 11 Chapter 3 Motion in a Straight Line, at BYJU’S:

  • NCERT Exemplar Class 11 Physics Solutions for Chapter 3 – Motion in a Straight Line
  • Class 11 Physics Chapter 3 Notes Motion in a Straight Line
  • Chapter 3 – Motion in a Straight Line
  • Motion in a Straight Line MCQs for NEET

Chapter 4: Motion in a Plane

Students will learn about the scalar and vector quantities and their difference. The method of performing algebraic expressions on various scalar quantities are also explained here. Besides, true or false questions based on these concepts and their justification are elaborated under each answer. We will also learn the concept of magnitude of vectors and their co-linearity, magnitude of displacement vector and the various types of displacement of a moving vehicle. It will help us to understand the time taken by a person to cross a river, experience of riding a bicycle in rain and a ball thrown by a cricketer in the ground.

Topics Covered in Class 11 Physics Chapter 4 Motion in a Plane

Scalar and vector quantities: Position and displacement vectors, general vectors and notation, equality of vectors, multiplication of vectors by a real number; addition and subtraction of vectors. Relative velocity. Unit vectors. Resolution of a vector in a plane – rectangular components. Motion in a plane. Cases of uniform velocity and uniform acceleration – projectile motion. Uniform circular motion.

Also, access the following resources for Class 11 Chapter 4 Motion in a Plane, at BYJU’S:

  • CBSE Physics Notes Class 11 Chapter 4 Motion in a Plane
  • Chapter 4 – Motion in a Plane
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 4 – Motion in a Plane

Chapter 5: Laws of Motion

This chapter is very important in mechanics. Problems based on the conservation of momentum are frequently asked in the exam. By going through this chapter, students will become well-versed with the laws of motion and their applications in our daily activities. Various numerical problems based on mechanics are solved clearly in this chapter to boost the exam preparation of students. Having a good knowledge of these concepts, students will be able to pursue well in their higher education levels.

Topics Covered in Class 11 Physics Chapter 5 Laws of Motion

Intuitive concept of force. Inertia, Newton’s first law of motion; momentum and Newton’s second law of motion; impulse; Newton’s third law of motion. Law of conservation of linear momentum and its applications. Equilibrium of concurrent forces. Static and kinetic friction, laws of friction, rolling friction, lubrication. Dynamics of uniform circular motion: Centripetal force, examples of circular motion (vehicle on level circular road, vehicle on banked road).

Also, access the following resources for Class 11 Chapter 5 Laws of Motion, at BYJU’S:

  • NCERT Exemplar Class 11 Physics Solutions for Chapter 5 – Laws Of Motion
  • Laws Of Motion Class 11 Notes

Chapter 6: Work, Energy and Power

The Work Energy Theorem is an important concept in this chapter. Students are highly recommended to learn this chapter effectively as it is continued in future classes also. The work done by a person and the energy required to do that work is explained briefly with suitable examples to make the students well-versed with the concepts. Problems on determining the energy and power are solved in a step-wise manner based on the mark weightage allotted by the CBSE board. Practising these concepts regularly will make them master the chapter effortlessly.

Topics Covered in Class 11 Physics Chapter 6 Work, Energy and Power

Scalar product of vectors. Work done by a constant force and a variable force; kinetic energy, work-energy theorem, power. Notion of potential energy, potential energy of a spring, conservative forces; conservation of mechanical energy (kinetic and potential energies); non-conservative forces; elastic and inelastic collisions in one and two dimensions.

Also, access the following resources for Class 11 Chapter 6 Work, Energy and Power, at BYJU’S:

  • Work, Energy and Power Class 11 Notes
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 6 – Work, Energy and Power

Chapter 7: System of Particles and Rotational Motion

This chapter will help students understand the motion of extended bodies, such as the system of particles. The centre of mass of a system of particles is the main concept in this chapter. The term motion and its usefulness are briefly explained as per the syllabus of the CBSE board. As many concepts are covered under this chapter, students are highly recommended to make use of a perfect study material while answering the exercise questions from the textbook.

Topics Covered in Class 11 Physics Chapter 7 System of Particles and Rotational Motion

Centre of mass of a two-particle system, momentum conservation and centre of mass motion. Centre of mass of a rigid body; centre of mass of circular ring, disc, rod and sphere. Vector product of vectors; moment of a force, torque, angular momentum, conservation of angular momentum with some examples.

Equilibrium of rigid bodies, rigid body rotation and equation of rotational motion, comparison of linear and rotational motions; moment of inertia, radius of gyration. Values of M.I. for simple geometrical objects (no derivation). Statement of parallel and perpendicular axes theorems and their applications.

Also, access the following resources for Class 11 Chapter 7 System of Particles and Rotational Motion, at BYJU’S:

  • System of Particles and Rotational Motion Class 11 Notes
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 7 – System of Particles and Rotational Motion
  • Physics Revision Notes for Class 11 Chapter 7 System of Particles and Rotational Motion

Chapter 8: Gravitation

We know that all material objects are attracted towards the Earth. The things which we throw up fall down. Climbing a hill is difficult when compared to going downhill. Gravitation is a very popular concept as most of them which we study in the future are in accordance with this phenomenon. To understand the more complex concepts in this chapter, students should know the difference between gravity and gravitation. The other concepts discussed in this chapter are potential energy difference between two points, acceleration due to gravity and interplanetary motion.

Topics Covered in Class 11 Physics Chapter 8 Gravitation

Kepler’s laws of planetary motion. The universal law of gravitation. Acceleration due to gravity and its variation with altitude and depth. Gravitational potential energy; gravitational potential. Escape speed, orbital velocity of a satellite. Geostationary satellites.

Also, access the following resources for Class 11 Chapter 8 Gravitation, at BYJU’S:

  • Gravitation Class 11 Notes
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 8 – Gravitation

Chapter 9: Mechanical Properties of Solids

A rigid body has a definite shape and size, but in reality, it is bent, stretched and compressed. A force is necessary in order to know the shape of a solid. The concepts of importance in this chapter are plasticity and elasticity. Students will learn about the mechanical properties of a solid, Young’s Modulus of copper and steel and the yield strength. Problems based on these concepts appear in the exams for more marks, so it is necessary to practise them on a daily basis. Students will also get to know about the stress-strain relationship graph, which is very important for the exam.

Topics Covered in Class 11 Physics Chapter 9 Mechanical Properties of Solids

Elastic behaviour, stress-strain relationship, Hooke’s law, Young’s modulus, bulk modulus, shear, modulus of rigidity.

Also, access the following resources for Class 11 Chapter 9 Mechanical Properties of Solids, at BYJU’S:

  • CBSE Class 11 Physics Notes Chapter 9 Mechanical Properties of Solids
  • Physics Revision Notes for Class 11 Chapter 9 Mechanical Properties of Solids
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 9 – Mechanical Properties of Solids

Chapter 10: Mechanical Properties of Fluids

Here, we will learn about the physical properties of liquids and gases. They are called as fluids as they have the capacity to flow. This is an important property which separates solids from liquids and gases. The other important concepts covered here are Bernoulli’s principle , Reynold’s number, streamline flow, viscosity and surface tension. The fundamental property of a fluid is that it can flow. It has no resistance to change its shape. Students will get a clear picture about the mechanical properties of fluids which are of more marks in the final exam.

Topics Covered in Class 11 Physics Chapter 10 Mechanical Properties of Fluids

Pressure due to a fluid column; Pascal’s law and its applications (hydraulic lift and hydraulic brakes). Effect of gravity on fluid pressure. Viscosity, Stokes’ law, terminal velocity, Reynold’s number, streamline and turbulent flow.

Bernoulli’s theorem and its applications. Surface energy and surface tension, angle of contact, application of surface tension ideas to drops, bubbles and capillary rise.

Also, access the following resources for Class 11 Chapter 10 Mechanical Properties of Fluids, at BYJU’S:

  • Mechanical Properties of Fluids Class 11 Notes
  • Physics Revision Notes for Class 11 Chapter 10 Mechanical Properties of Fluids
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 10 – Mechanical Properties of Fluids

Chapter 11: Thermal Properties of Matter

We all are familiar with heat and temperature. The method used to determine the temperature is covered in this chapter. Students will also get a clear idea about Newton’s Law of Cooling, which is an important concept for various competitive exams. Temperature is the hotness possessed by a body that can be measured using a thermometer. The various thermal properties of matter are listed in a step-wise manner in this chapter to make students more confident about the concepts.

Topics Covered in Class 11 Physics Chapter 11 Thermal Properties of Matter

Heat, temperature, thermal expansion; specific heat capacity – calorimetry; change of state – latent heat. Heat transfer – conduction, convection and radiation, thermal conductivity, Newton’s law of cooling.

Also, access the following resources for Class 11 Chapter 11 Thermal Properties of Matter, at BYJU’S:

  • CBSE Class 11 Physics Notes Chapter 11 Thermal Properties of Matter
  • Physics Revision Notes for Class 11 Chapter 11 Thermal Properties of Matter
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 11 – Thermal Properties of Matter

Chapter 12: Thermodynamics

Thermodynamics is a concept of heat and temperature and its conversion to other energy forms. It is one of the main topics which the question paper setters focus on, and most of the questions in the exams can appear from this chapter. In order to attain remarkable grades, it is crucial for students to learn all these concepts effectively. The laws of thermodynamics, specific heat capacity, various thermodynamic processes and the Carnot engine are some of the important concepts covered in this chapter.

Topics Covered in Class 11 Physics Chapter 12 Thermodynamics

Thermal equilibrium and definition of temperature (zeroth law of thermodynamics). Heat, work and internal energy. First law of thermodynamics. Second law of thermodynamics: Reversible and irreversible processes. Heat engines and refrigerators.

Also, access the following resources for Class 11 Chapter 12 Thermodynamics, at BYJU’S:

  • CBSE Class 11 Physics Notes Thermodynamics
  • Physics Revision Notes for Class 11 Chapter 12 Thermodynamics
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 12 – Thermodynamics

Chapter 13: Kinetic Theory

This chapter is a more scoring section when it comes to exam preparation. Apart from the properties of solids and liquids, the properties of gases are easy to understand. Students will learn concepts like molecular nature of matter, behaviour of gases, kinetic theory of  an ideal gas, law of equipartition of energy , specific heat capacity and mean free path in this chapter. The problems are also solved in a systematic manner following the CBSE guidelines so that scoring good marks would be an easy task for the Class 11 students.

Topics Covered in Class 11 Physics Chapter 13 Kinetic Theory

Equation of state of a perfect gas, work done on compressing a gas. Kinetic theory of gases: Assumptions, concept of pressure. Kinetic energy and temperature; rms speed of gas molecules; degrees of freedom, law of equipartition of energy (statement only) and application to specific heat capacities of gases; concept of mean free path, Avogadro’s number.

Also, access the following resources for Class 11 Chapter 13 Kinetic Theory, at BYJU’S:

  • CBSE Class 11 Physics Notes Chapter 13 Kinetic Theory
  • Physics Revision Notes for Class 11 Chapter 13 Kinetic Theory
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 13 – Kinetic Theory

Chapter 14: Oscillations

Oscillations are one of the basic concepts in Physics. It is very important for the students to learn the concepts from this chapter, as it will be continued in further classes as well. The concepts explained in this chapter are periodic and oscillatory motions , simple harmonic motion, uniform circular motion etc. To learn these concepts effectively, it is necessary for the students to follow suitable study material for this purpose. By learning the chapter on a daily basis, students will be able to face the more complex questions that would arise in the exam.

Topics Covered in Class 11 Physics Chapter 14 Oscillations

Periodic motion – period, frequency, displacement as a function of time. Periodic functions. Simple harmonic motion (SHM) and its equation; phase; oscillations of a spring – restoring force and force constant; energy in SHM – kinetic and potential energies; simple pendulum – derivation of expression for its time period; free, forced and damped oscillations (qualitative ideas only), resonance.

Also, access the following resources for Class 11 Chapter 14 Oscillations, at BYJU’S:

  • CBSE Class 11 Physics Notes Chapter 14 Oscillations
  • Physics Revision Notes for Class 11 Chapter 14 Oscillations
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 14 – Oscillations

Chapter 15: Waves

This chapter contains comprehensive questions on important concepts like wave dynamics. Questions present in this chapter will assist students through concepts like the types of waves , speed of sound in air, the tension on strings and the dependence of the speed of sound in air. The important formulas and concepts are highlighted in the solutions to make a revision of concepts easier for the students. The various wave characteristics, such as amplitude, frequency, phase, wavelength, displacement of waves and resonance, are covered in this chapter.

Topics Covered in Class 11 Physics Chapter 15 Waves

Wave motion. Longitudinal and transverse waves, speed of wave motion. Displacement relation for a progressive wave. Principle of superposition of waves, reflection of waves, standing waves in strings and organ pipes, fundamental mode and harmonics. Beats. Doppler effect.

Also, access the following resources for Class 11 Chapter 15 Waves, at BYJU’S:

  • CBSE Class 11 Physics Notes Chapter 15 Waves
  • Physics Revision Notes for Class 11 Chapter 15 Waves
  • NCERT Exemplar Class 11 Physics Solutions for Chapter 15 – Waves

As there are many concepts present in each chapter, students have to revise the concepts on a regular basis to get a grip on them. It will help them to understand the right way of approaching the difficult questions in the final exam. NCERT Class 11 Books can be accessed by the students to get a clear understanding of the syllabus.

Features of BYJU’S NCERT Solutions for Class 11 Physics

The Class 11 Physics NCERT Solutions provided by BYJU’S have the following features:

  • Elaborate explanations for all the textbook questions.
  • A systematic process for answering numerical problems.
  • Clear-cut answers for all the questions based on theory.
  • Authentic information from highly experienced subject matter experts.
  • Solutions are present in both online and offline modes.

Note: Class 11 Physics students (who are studying under the CBSE syllabus) can bookmark this page in their browser to easily access NCERT Solutions for Class 11 Physics in the future.

CBSE Marking Scheme 2023-24

CBSE board has divided the academic sessions covering the entire syllabus to help students learn the concepts effectively. A systematic approach is followed based on the interconnectivity of topics and concepts by the experts. The exams will be conducted by the CBSE board at the end of the academic year as per the bifurcated syllabus. This basically improves the condition of having board-conducted classes at the end of the year.

Why Should One Opt for BYJU’S NCERT Solutions?

The NCERT Solutions at BYJU’S are the best study material for students under the CBSE board. The content provided is accurate, and students can rely on these solutions to perform better in the annual exam. The solutions strictly follow the NCERT Class 11 Physics Syllabus , which is prescribed by the CBSE board. Some of the advantages of using the NCERT Solutions provided by us are given below.

  • Top-notch experts prepare the solutions

The NCERT Solutions have been prepared by a set of highly experienced faculty at BYJU’S with the main aim of making quality educational content for each student. The precise and informative solutions are considered to be the best among all the other materials available online.

  • Students will be able to answer complex questions in the exam

The NCERT Solutions at BYJU’S are famous for being student-friendly and easy to understand. Answers to difficult questions and problems are explained in steps to help students understand the method of solving them easily. The solutions provided are concept-focused and not question focused, which enables the students to face the different questions that would arise in the exam.

  • The best study material for revision

After learning all the chapters, students are advised to revise all the concepts a month prior to the exam. This will help them to remember all the problems and concepts which are important from the exam perspective. It will also help them to memorise all the formulas and problems which are of high marks as per the CBSE exam pattern.

After Going through Our Class 11 Physics NCERT Solutions, Also Explore,

  • NCERT Exemplar Problems for Class 11 Physics
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NCERT Solutions for Class 11 Physics Chapter 3 Free PDF Download

Ncert solutions for class 11 physics chapter 3 – motion in straight line.

This article deals with NCERT Solutions for Class 11 Physics Chapter 3. Physics is a pretty difficult subject. However, students should not worry since NCERT Solutions are here to help. The main objective of NCERT Solutions is to make top-notch study material. Furthermore, the explanation of the content in NCERT Solutions makes memorization easy. These solutions are certainly self-explanatory. Also, there are exercises and questions between the chapters.

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Download NCERT Solutions for Class 11 here.

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CBSE Class 11 Physics Chapter 3 Motion in Straight Line NCERT Solutions

NCERT Solutions for Class 11 Physics Chapter 3 deals with Motion in Straight Line. First of all, motion refers to a change in position of an object. Furthermore, this change is with respect to the surroundings of the object. Also, this change takes place in a given interval of time. Motion is certainly common to everything in the Universe. Most noteworthy, this chapter is a part of kinetics. The chapter contains information about rectilinear motion here. There is also information here about reference point and frame of reference. The chapter also deals with average velocity and speed. There is also a discussion of instantaneous velocity and speed. Acceleration is also a part of this chapter.

Subtopics covered under NCERT Solutions for Class 11 Physics Chapter 3

  • 3.1 Introduction
  • 3.2 Position, path length, and displacement
  • 3.3 Average velocity and average speed
  • 3.4 Instantaneous velocity and speed
  • 3.5 Acceleration
  • 3.6 Kinematic equations for uniformly accelerated motion
  • 3.7 Relative velocity

NCERT Solutions for Class 11 Physics Chapter 3

Motion is a topic that has extreme usage. In every field of science, motion is essential. Furthermore, the chapter is vital for automobiles companies. This is because acceleration, speed, and velocity are very important in automobiles. Also, engineers consistently make use of motion-related concepts. This chapter will certainly prepare students in astronomy. This is due to the study of motion of heavenly bodies and other issues in astronomy.

Below is a brief discussion of the sub-units of the chapter:

3.1 Introduction –

This part certainly gives a general idea about this topic. It introduces students to this chapter.

3.2 Position, path length, and displacement –

This sub-unit discusses three aspects of motion. Above all, these aspects are Position, path length, and displacement.

3.3 Average velocity and average speed –

Average velocity changes in displacement divided by the time intervals. Furthermore, these time intervals are those in which the displacement occurs. In contrast, average speed describes the rate of motion over the actual path.

3.4 Instantaneous velocity and speed –

The velocity of an instant is the limit of the average velocity as the time interval gets infinitely small. This is clearly in contrast to instantaneous speed. Instantaneous speed refers to the magnitude of velocity.

3.5 Acceleration –

This refers to the rate of change of velocity of an object with respect to time.

3.6 Kinematic equations for uniformly accelerated motion –

This part has simple equations. Most noteworthy, these equations relate various aspects of motion.

3.7 Relative velocity –

This is an aspect of velocity. Above all, this is the velocity of an object in the rest frame of another object.

You can download NCERT Solutions for Class 11 Physics Chapter 3 PDF by clicking on the button below.

NCERT Solutions for Class 11 Physics Chapter 3 Free PDF Download

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NCERT Solutions for Class 11

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  • NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line
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NCERT Solutions for Class 11 Physics Chapter 3

For many students, if you ask them what's their favourite subject in school, the answer would be Physics. There is no doubt Physics has won the hearts of every student. Indeed, it's not easy to understand Physics concepts, but the subject is so much fun to learn that students give their full concentration. Thus, things become easier for them. With our help, you will get to know all the small details present in NCERT Physics Class 11 Chapter 3, which you might miss when you are studying all by yourself.

Would you like to view a summarized version of this chapter? Check out the 'Chapter at a glance' section below the PDF of NCERT Solutions.

Motion in a Straight Line Chapter at a Glance - Class 11 NCERT Solutions

An object is said to be in motion if its position changes with time. The position of the object can be specified with reference to a conveniently chosen origin. For motion in a straight fine. position to the right of the origin is taken as positive and to the left as negative.

Path length is defined as the total length of the path traversed by an object.

Displacement is the change in position: $\Delta x=x_{2}-x_{1} $ Path length is greater or equal to the magnitude of the displacement between the same points.

An object is said to be in uniform motion in a straight line if its displacement is equal in equal intervals of time. Otherwise, the motion is said to be nonuniform

Average velocity is the displacement divided by the time Interval in which the displacement occurs:

$ v\bar{}=\frac{\Delta x}{\Delta t}$

On an x-t graph. The average velocity over a time Interval is the slope of the line connecting the initial and final positions corresponding to that interval.

Average Speed is the ratio of total path length traversed and the corresponding time Interval.

Instantaneous velocity or simply velocity is defined as the limit of the average velocity as the time interval $\Delta t$ becomes infinitesimally small

$v=\lim_{\Delta t\rightarrow 0}v\bar{}=\lim_{\Delta t\rightarrow 0}\frac{\Delta x}{\Delta t}=\frac{dx}{dt}$

The velocity at a particular instant is equal to the slope of the tangent drawn on position-time graph at that instant.

Average acceleration is the change in velocity divided by the time interval during which the change occurs: $a\vec{}=\frac{\Delta v}{\Delta t}$

Instantaneous acceleration is defined as the limit of the average acceleration as the time interval at goes to zero:

$a=\lim_{\Delta \rightarrow t}a\vec{}=\lim_{\Delta t\rightarrow 0}\frac{\Delta t}{\Delta v}=\frac{dv}{dt}$

The acceleration of an object at a particular time is the slope of the velocity-time graph at that instant of time. For uniform motion. acceleration is zero and the x-t graph is a straight line inclined to the time axis and the v-t graph is a straight line parallel to the time axis. For motion with uniform acceleration. x - t graph is a parabola while the v-t graph is a straight line inclined to the time axis.

The area under the velocity-time curve between times t 1 and t 2 is equal to the displacement of the object during that interval of time.

For objects in uniformly accelerated rectilinear motion. the five quantities, displacement x, time taken t. Initial velocity v 0,  final velocity v and acceleration a are related by a set of simple equations called kinematic equations of motion:

x=v 0 t+$\frac{1}{2}$at 2

v 2 =$v_{0}^{2}$+2ax

For Uniform Motion

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For Non-Uniform Motion

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The position of an object moving along x-axis is given by x = a + bt 2 , where a = 8.5 m, b = 2.5 ms –2 and t is measured in seconds. What is its velocity at t = 0 s and t = 2.0 s.? What is the average velocity between t = 2.0 s and t = 4.0 s? 

Access NCERT Solutions for Class 11 Physics  Chapter 3 - Motion in a Straight Line

1. In which of the following examples of motion, can the body be considered approximately a point object:

(a) a railway carriage moving without jerks between two stations.

Ans: As the size of a carriage is very small as compared to the distance between two stations, the carriage can be treated as a point sized object.

(b) a monkey sitting on top of a man cycling smoothly on a circular track.

Ans: As the size of a monkey is very small as compared to the size of a circular track, the monkey can be considered as a point sized object on the track.

(c) a spinning cricket ball that turns sharply on hitting the ground.

Ans: As the size of a spinning cricket ball is comparable to the distance through which it turns sharply on hitting the ground, the cricket ball cannot be considered as a point object.

(d) a tumbling beaker that has slipped off the edge of a table.

Ans: As the size of a beaker is comparable to the height of the table from which it slipped, the beaker cannot be considered as a point object.

2. The position-time (x-t) graphs for two children A and B returning from their school O to their homes P and Q respectively are shown in figure. Choose the correct entries in the brackets below:

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a. (A/B) lives closer to the school than (B/A)

Ans: From the graph, it is clear that $OP<OQ$. Therefore, A lives closer to the school than B.

b. (A/B) starts from the school earlier than (B/A)

Ans: From the graph it is clear that for \[x\text{ }=\text{ }0,\text{ }t\text{ }=\text{ }0\] for A and t has some finite value for B. Hence, A starts from the school earlier than B.

c. (A/B) walks faster than (B/A)

Ans: As the velocity is equal to slope of x-t graph, in case of uniform motion and slope of x-t graph for B is greater than that for A. Thus B walks faster than A.

d. A and B reach home at the (same/different) time

Ans: From the graph it is clear that both A and B reach their respective homes at the same time.

e.  (A/B) overtakes (B/A) on the road (once/twice).

Ans: As B moves later than A and his/her speed is greater than that of A. From the graph, it is clear that B overtakes A only once on the road.

3. A woman starts from her home at 9.00 am, walks with a speed of \[5\text{ }km/hr\] on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of \[25\text{ }km/hr\]. Choose suitable scales and plot the x-t graph of her motion

Ans: In the above question it is given that:

Speed of the woman \[=\text{ }5\text{ }km/h\].

Distance between her office and home \[=\text{ }2.5\text{ }km\].

\[Time\text{ }taken\text{ }=\text{ }Distance\text{ }/\text{ }Speed\]

\[=\text{ }2.5\text{ }/\text{ }5\text{ }=\text{ }0.5\text{ }h\text{ }=\text{ }30\text{ }min\]

It is given that she covers the same distance in the evening by an auto.

Now, \[speed\text{ }of\text{ }the\text{ }auto\text{ }=\text{ }25\text{ }km/h\].

\[=\text{ }2.5\text{ }/\text{ }25\text{ }=\text{ }1\text{ }/\text{ }10\text{ }=\text{ }0.1\text{ }h\text{ }=\text{ }6\text{ }min\]

The suitable x-t graph of the motion of the woman is shown in the given figure.

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4. A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. Plot the x-t graph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.

Distance covered with 1 step \[=\text{ }1\text{ }m\]

Time taken \[=\text{ }1\text{ }s\]

Time taken to move first \[5\text{ }m\] forward \[=\text{ }5\text{ }s\]

Time taken to move \[3\text{ }m\]backward \[=\text{ }3\text{ }s\]

\[Net\text{ }distance\text{ }covered\text{ }=\text{ }5\text{ }\text{ }3\text{ }=\text{ }2\text{ }m\]

Net time taken to cover \[2\text{ }m\text{ }=\text{ }8\text{ }s\].

Drunkard covers \[2\text{ }m\]in \[8\text{ }s\].

Drunkard covered \[4\text{ }m\]in \[16\text{ }s\].

Drunkard covered \[6\text{ }m\]in $2\text{4 s}$.

Drunkard covered \[8\text{ }m\]in \[32\text{ }s\].

In the next \[5\text{ }s\], the drunkard will cover a distance of \[5\text{ }m\] and a total distance of \[13\text{ }m\] and then fall into the pit.

Net time taken by the drunkard to cover $km$\[13\text{ }m\text{ }=\text{ }32\text{ }+\text{ }5\text{ }=\text{ }37\text{ }s\]

The x-t graph of the drunkard’s motion can be shown below:

(Image will be uploaded soon)

5. A jet airplane travelling at the speed of \[500\text{ }km/hr\] ejects its products of combustion at the speed of \[1500\text{ }km/hr\] relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?

Speed of the jet airplane, \[=\text{ }500\text{ }km/hr\]

Relative speed of its products of combustion with respect to the plane,\[=1500\text{ }km/hr\].

Speed of its products of combustion with respect to the ground $=1500-500=1000km/hr$

Hence, the speed of the latter with respect to an observer on the ground is $1000km/hr$.

6. A car moving along a straight highway with speed of \[126\text{ }km/hr\] is brought to a stop within a distance of 200 m. What is the retardation of the car (assumed uniform), and how long does it take for the car to stop?

Initial velocity of the car is \[u=126\text{ }km/hr=35m/s\]. 

Final velocity of the car is $v=0km/hr$.

Distance covered by the car before coming to rest is \[200\text{ }m\].

Consider retardation produced in the car $=a$

From third equation of motion, ${{v}^{2}}-{{u}^{2}}=2as$

Therefore, $-{{35}^{2}}=2a\left( 200 \right)$

$a=-3.0625m/{{s}^{2}}$

From first equation of motion, time (t) taken by the car to stop can be obtained as:

$0=35-\left( 3.065 \right)t$

Hence, the retardation of the car (assumed uniform) is $3.0625m/{{s}^{2}}$, and it takes $11.44s$ for the car to stop.

7. Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of \[72\text{ }km/hr\] in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by \[1\text{ }m\text{ }{{s}^{-2}}\]. If after 50 s, the guard of B just brushes past the driver of A, what was the original distance between them?

For train A: Initial velocity is \[u\text{ }=\text{ }72\text{ }km/h\text{ }=\text{ }20\text{ }m/s\]

Time is \[t=50\text{ }s\].

Acceleration, ${{a}_{1}}=0$ (Since it is moving with a uniform velocity)

From second equation of motion, distance $\left( {{s}_{1}} \right)$ covered by train A can be obtained as:

$s=ut+\left( 1/2 \right)a{{t}^{2}}$

$=20\times 50+0=1000m$

For train B:

Initial velocity is \[u\text{ }=\text{ }72\text{ }km/h\text{ }=\text{ }20\text{ }m/s\]

Acceleration, $a=1m/{{s}^{2}}$

From second equation of motion, distance $\left( {{s}_{n}} \right)$ covered by train A can be obtained as:

${{s}_{n}}=ut+\left( 1/2 \right)a{{t}^{2}}$

$=20\times 50+\left( 1/2 \right)\left( 1 \right){{\left( 50 \right)}^{2}}=2250m$

\[Length\text{ }of\text{ }both\text{ }trains\text{ }=\text{ }2\text{ }\times \text{ }400\text{ }m\text{ }=\text{ }800\text{ }m\]

Therefore, the original distance between the driver of train A and the guard of train B is \[2250-1000\text{ }-\text{ }800\text{ }=\text{ }450m.\]

8. On a two-lane road, car A is travelling with a speed of \[36\text{ }km/hr\]. Two cars B and C approach car A in opposite directions with a speed of \[54\text{ }km/hr\] each. At a certain instant, when the distance AB is equal to AC, both being 1 km, B decides to overtake A before C does. What minimum acceleration of car B is required to avoid an accident?

Velocity of car A is \[36\text{ }km/hr=10m/s\] .

\[Velocity\text{ }of\text{ }car\text{ }B\text{ }=\text{ }Velocity\text{ }of\text{ }car\text{ }C=54km/hr=15m/s\].

Relative velocity of car A with respect to car B,

= 15 – 10 = 5 m/s

Relative velocity of car A with respect to car C,

\[=\text{ }15\text{ }+\text{ }10\text{ }=\text{ }25\text{ }m/s\]

At a certain instance, both cars B and C are at the same distance from car A. 

Hence, \[s\text{ }=\text{ }1\text{ }km\text{ }=\text{ }1000\text{ }m\].

Time taken (t) by car C to cover \[1000\text{ }m\] (i.e., to overtake A) \[=\text{ }1000\text{ }/\text{ }25\text{ }=\text{ }40\text{ }s\].

Thus, to avoid an accident, car B must cover the same distance in a maximum of \[40\text{ }s\].

Using second equation of motion, minimum acceleration (a) produced by car B will be:

$1400=\left( 15\times 40 \right)+\left( \frac{1}{2}\times a\times {{\left( 40 \right)}^{2}} \right)$

$\Rightarrow a=1m/{{s}^{2}}$

Hence, the minimum acceleration of car B required to avoid an accident is $1m/{{s}^{2}}$.

9. Two towns A and B are connected by a regular bus service with a bus leaving in either direction every T minutes. A man cycling with a speed of \[20\text{ }km/hr\] in the direction A to B notices that a bus goes past him every 18 min in the direction of his motion, and every 6 min in the opposite direction. What is the period T of the bus service and with what speed (assumed constant) do the buses ply on the road?

Consider V to be the speed of the bus running between towns A and B.

Speed of the cyclist is \[v=20\text{ }km/hr\] .

Relative speed of the bus moving in the direction of the cyclist will be $V-v=\left( V-20 \right)m/s$.

The bus went past the cyclist every \[18\] min i.e., \[18\text{ }/\text{ }60\text{ }h\] (when he moves in the direction of the bus).

Hence, distance covered by the bus \[=\text{ }\left( V\text{ }-\text{ }20 \right)\text{ }\times \text{ }18\text{ }/\text{ }60\text{ }km\] ...... (i)

As one bus leaves after every T minutes, the distance travelled by the bus will be \[=V\text{ }\times \text{ }T\text{ }/\text{ }60\] ...... (ii)

As equations (i) and (ii) are equal.

\[\left( V\text{ }-\text{ }20 \right)\text{ }\times \text{ }18\text{ }/\text{ }60\text{ }=\text{ }VT\text{ }/\text{ }60\] ...... (iii)

Relative speed of the bus moving in the opposite direction of the cyclist will be \[\left( V\text{ }+\text{ }20 \right)\text{ }km/h\].

Thus, time taken by the bus to go past the cyclist \[=\text{ }6\text{ }min\text{ }=\text{ }6\text{ }/\text{ }60\text{ }hr\]

\[\Rightarrow \left( V\text{ }+\text{ }20 \right)\times 6\text{ }/\text{ }60\text{ }=\text{ }VT\text{ }/\text{ }60\] ...... (iv)

From (iii) and (iv), we get

\[\left( V\text{ }+\text{ }20 \right)\text{ }\times \text{ }6\text{ }/\text{ }60\text{ }=\text{ }\left( V\text{ }-\text{ }20 \right)\text{ }\times \text{ }18\text{ }/\text{ }60\]

\[V\text{ }+\text{ }20\text{ }=\text{ }3V\text{ }\text{ }60\]

\[2V\text{ }=\text{ }80\]

\[V\text{ }=\text{ }40\text{ }km/h\], which is the required speed.

Substituting the value of V in equation (iv), 

\[\left( 40\text{ }+\text{ }20 \right)\text{ }\times \text{ }6\text{ }/\text{ }60\text{ }=\text{ }40T\text{ }/\text{ }60\]

\[T\text{ }=\text{ }360\text{ }/\text{ }40\text{ }=\text{ }9\text{ }min\], which is the required time period.

10. A player throws a ball upwards with an initial speed of \[29.4\text{ }m/s\].

a. What is the direction of acceleration during the upward motion of the ball?

Ans: Acceleration of the ball (which is actually acceleration due to gravity) always acts in the downward direction towards the centre of the Earth, irrespective of the direction of the motion of the ball.

b. What are the velocity and acceleration of the ball at the highest point of its motion?

Ans: Acceleration due to gravity at a given place is constant and acts on the ball at all points (including the highest point) with a constant value i.e.,n\[g\text{ }=\text{ }9.8\text{ }m/{{s}^{2}}\]. At maximum height, velocity of the ball becomes zero.

c. Choose the x = 0 m and t = 0 s to be the location and time of the ball at its highest point, vertically downward direction to be the positive direction of x-axis, and give the signs of position, velocity and acceleration of the ball during its upward, and downward motion.

Ans: The sign of position is positive, sign of velocity is negative, and sign of acceleration is positive during upward motion. During downward motion, the signs of position, velocity, and acceleration are all positive.

d. To what height does the ball rise and after how long does the ball return to the player’s hands? (Take \[g\text{ }=\text{ }9.8\text{ }m/{{s}^{2}}\] and neglect air resistance).

Ans: Initial velocity of the ball, \[u\text{ }=\text{ }29.4\text{ }m/s\].

Final velocity of the ball, \[v\text{ }=\text{ }0\] (At maximum height, the velocity of the ball becomes zero)

Acceleration, \[a=g\text{ }=9.8\text{ }m/{{s}^{2}}\]

From first equation of motion, 

$0=-29.4+\left( 9.8 \right)t$

$t=\frac{29.4}{9.8}=3s$

\[Time\text{ }of\text{ }ascent\text{ }=\text{ }Time\text{ }of\text{ }descent\]

Hence, the total time taken by the ball to return to the player’s hands\[=\text{ }3\text{ }+\text{ }3\text{ }=\text{ }6\text{ }s\].

11. Read each statement below carefully and state with reasons and examples, if it is true or false; A particle in one-dimensional motion

a. with zero speed at an instant may have non-zero acceleration at that instant

Ans: The above statement is true. When an object is thrown vertically up in the air, its speed becomes zero at maximum height. It has acceleration equal to the acceleration due to gravity (g) Which acts in the downward direction at that point.

b. with zero speed may have non-zero velocity,

Ans: The above statement is false as speed is the magnitude of velocity. If speed is zero, the magnitude of velocity along with the velocity is zero.

c. with constant speed must have zero acceleration,

Ans: The above statement is true. If a car is moving on a straight highway with constant speed, it will have constant velocity. Acceleration is defined as the rate of change of velocity. Hence, the acceleration of the car is also zero.

d. with a positive value of acceleration must be speeding up.

Ans: The above statement is false. If acceleration is positive and velocity is negative at the instant time is taken as origin. Thus, for all the time before velocity becomes zero, there is slowing down of the particle. This case occurs when a particle is projected upwards. This statement will be true when both velocity and acceleration are positive, at that instant time taken as origin. This case happens when a particle is moving with positive acceleration or falling vertically downwards from a height.

12. A ball is dropped from a height of 90 m on a floor. At each collision with the floor, the ball loses one tenth of its speed. Plot the speed-time graph of its motion between \[\mathbf{t}\text{ }=\text{ }\mathbf{0}\text{ }\mathbf{to}\text{ }\mathbf{12}\text{ }\mathbf{s}\].

Ball is dropped from a height is \[s\text{ }=\text{ }90\text{ }m\].

Initial velocity of the ball is \[u\text{ }=\text{ }0\].

Acceleration is $a=g=9.8m/{{s}^{2}}$.

Final velocity of the ball to be v.

Using second equation of motion, time (t) taken by the ball to hit the ground can be obtained

$90=0+\left( 1/2 \right)9.8{{t}^{2}}$

$t=\sqrt{18.38}=4.29s$

Using, first equation of motion, final velocity is given as:

$v=0+9.8\left( 4.29 \right)=42.04m/s$

Rebound velocity of the ball is calculated as:

${{u}_{r}}=9v/10=9\left( \frac{42.04}{10} \right)=37.84m/s$

Time (t) taken by the ball to reach maximum height is obtained with the help of first equation of motion as:

$v={{u}_{r}}+at'$

$0=37.84+\left( -9.8 \right)t'$

$t'=37.84/9.8=3.86s$

Total time taken by the ball will be $t+t'=4.29+3.86=8.15s$.

As the time of ascent is equal to the time of descent, the ball takes \[3.86\text{ }s\] to strike back on the floor for the second time.

The velocity with which the ball rebounds from the floor will be ${{u}_{r}}=9v/10=9\left( \frac{37.84}{10} \right)=34.05m/s$

Total time taken by the ball for second rebound will be $t+t'=8.15+3.86=12.01s$

The speed-time graph of the ball is represented in the given figure as:

13. Explain clearly, with examples, the distinction between:

a. magnitude of displacement (sometimes called distance) over an interval of time, and the total length of path covered by a particle over the same interval;

Ans: The shortest distance (which is a straight line) between the initial and final positions of the particle gives the magnitude of displacement over an interval of time. The total path length of a particle is the actual path length covered by the particle in a given interval of time. For example, suppose a particle moves from point A to point B and then comes back to a point, C taking a total time t, as shown below. Then, the magnitude of displacement of the particle is AC.

Whereas, total path length \[=\text{ }AB\text{ }+\text{ }BC\]

We know that the magnitude of displacement can never be greater than the total path length. But, in some cases, both quantities are equal to each other.

b. magnitude of average velocity over an interval of time, and the average speed over the same interval. Average speed of a particle over an interval of time is defined as the total path length divided by the time interval. Show in both (a) and (b) that the second quantity is either greater than or equal to the first. When is the equality sign true? (For simplicity, consider one-dimensional motion only).

Ans: We know that: 

\[Magnitude\text{ }of\text{ }average\text{ }velocity\text{ }=\text{ }Magnitude\text{ }of\text{ }displacement\text{ }/\text{ }Time\text{ }interval\]

Hence, for the given particle,

Average velocity $=AC/t$

\[Average\text{ }speed\text{ }=\text{ }Total\text{ }path\text{ }length\text{ }/\text{ }Time\text{ }interval\]

\[=\left( AB+BC \right)/t\]

Since, \[AB+BC>AC\], average speed is greater than the magnitude of average velocity. The two quantities will be equal if the particle continues to move along a straight line.

14. A man walks on a straight road from his home to a market 2.5 km away with a speed of \[5\text{ }km/hr\]. Finding the market closed, he instantly turns and walks back home with a speed of \[7.5\text{ }km/hr\].What is the

(a) magnitude of average velocity, and

(b) average speed of the man over the interval of time (i) 0 to 30 min, (ii) 0 to 50 min, (iii) 0 to 40 min ? (Note: You will appreciate from this exercise why it is better to define average speed as total path length divided by time, and not as magnitude of average velocity. You would not like to tell the tired man on his return home that his average speed was zero)

Time taken by the man to reach the market from home is ${{t}_{1}}=2.5/5=1/2hr=30\min $.

Time taken by the man to reach home from the market is ${{t}_{2}}=2.5/7.5=1/3hr=20\min $. 

Total time taken in the whole journey \[=\text{ }30\text{ }+\text{ }20\text{ }=\text{ }50\text{ }min\].

0 to 30 min

\[Average\text{ }velocity\text{ }=\text{ }Displacement/Time\]

\[Average\text{ }speed\text{ }=\text{ }Distance/Time\]

0 to 50 min

\[Time\text{ }=\text{ }50\text{ }min\text{ }=\text{ }50/60\text{ }=\text{ }5/6\text{ }h\]

\[Net\text{ }displacement\text{ }=\text{ }0\]

\[Total\text{ }distance\text{ }=\text{ }2.5\text{ }+\text{ }2.5\text{ }=\text{ }5\text{ }km\]

\[Average\text{ }velocity\text{ }=\text{ }Displacement\text{ }/\text{ }Time\text{ }=\text{ }0\]

\[Average\text{ }speed\text{ }=\text{ }Distance\text{ }/\text{ }Time\text{ }=\text{ }5/\left( 5/6 \right)\text{ }=\text{ }6\text{ }km/h\]

0 to 40 min

\[Speed\text{ }of\text{ }the\text{ }man\text{ }=\text{ }7.5\text{ }km/h\]

\[Distance\text{ }travelled\text{ }in\text{ }first\text{ }30\text{ }min\text{ }=\text{ }2.5\text{ }km\]

Distance travelled by the man (from market to home) in the next 10 min

\[=\text{ }7.5\text{ }\times \text{ }10/60\text{ }=\text{ }1.25\text{ }km\]

\[Net\text{ }displacement\text{ }=\text{ }2.5\text{ }\text{ }1.25\text{ }=\text{ }1.25\text{ }km\]

\[Total\text{ }distance\text{ }travelled\text{ }=\text{ }2.5\text{ }+\text{ }1.25\text{ }=\text{ }3.75\text{ }km\]

\[Average\text{ }velocity\text{ }=\text{ }Displacement\text{ }/\text{ }Time\text{ }=\text{ }1.25\text{ }/\text{ }\left( 40/60 \right)\text{ }=\text{ }1.875\text{ }km/h\]

\[Average\text{ }speed\text{ }=\text{ }Distance\text{ }/\text{ }Time\text{ }=\text{ }3.75\text{ }/\text{ }\left( 40/60 \right)\text{ }=\text{ }5.625\text{ }km/h\].

15. In Exercises 13 and 14, we have carefully distinguished between average speed and magnitude of average velocity. No such distinction is necessary when we consider instantaneous speed and magnitude of velocity. The instantaneous speed is always equal to the magnitude of instantaneous velocity. Why?

Ans: We know that instantaneous velocity is the first derivative of distance with respect to time.

Here, the time interval is so small that it is assumed that the particle does not change its direction of motion. Therefore, both the total path length and magnitude of displacement become equal in this interval of time. Thus, instantaneous speed is always equal to instantaneous velocity.

16. Look at the graphs (a) to (d) (figure) carefully and state, with reasons, which of these cannot possibly represent one-dimensional motion of a particle.

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a. Consider the x-t graph, given in fig (a). It does not represent the one-dimensional motion of the particle. This is because a particle cannot have two positions at the same instant of time.

b. Consider the x-t graph, given in fig (b). It does not represent the one-dimensional motion of the particle. This is because a particle can never have two values of velocity at the same instant of time.

c. Consider the x-t graph, given in fig (c). It does not represent the one-dimensional motion of the particle. This is because speed being a scalar quantity cannot be negative.

d. Consider the x-t graph, given in fig (d). It does not represent the one-dimensional motion of the particle. This is because the total path length travelled by the particle cannot decrease with time.

17. Figure shows the x-t plot of the one-dimensional motion of a particle. Is it correct to say from the graph that the particle moves in a straight line for $t<0$ and on a parabolic path for $t>0$? If not, suggest a suitable physical context for this graph.

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Ans: No, this is because the x-t graph does not represent the trajectory of the path followed by a particle. Also from the graph, it is clear that at \[t=0,\text{ }x=0\].

18. A police van moving on a highway with a speed of \[30\text{ }km/hr\] fires a bullet at a thief’s car speeding away in the same direction with a speed of \[192\text{ }km/hr\]. If the muzzle speed of the bullet is \[150\text{ }m/s\], with what speed does the bullet hit the thief’s car? (Note: Obtain that speed which is relevant for damaging the thief’s car).

Speed of the police van is \[{{v}_{p}}=30\text{ }km/hr=8.33m/s\].

Muzzle speed of the bullet is \[{{v}_{b}}=150\text{ }m/s\].

Speed of the thief’s car is \[{{v}_{t}}=192\text{ }km/hr=53.33m/s\].

As the bullet is fired from a moving van, its resultant speed will be: $150+8.33=158.33m/s$.

Since both the vehicles are moving in the same direction, the velocity with which the bullet hits the thief’s car can be obtained as:

${{v}_{bt}}={{v}_{b}}-{{v}_{t}}=158.33-53.33=105m/s$

19. Suggest a suitable physical situation for each of the following graphs (figure):

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Ans: Consider fig 3.22 given in the question:

a. From the x-t graph given it is clear that initially a body was at rest. Further, its velocity increases with time and attains an instantaneous constant value. The velocity then reduces to zero with an increase in time. Further, its velocity increases with time in the opposite direction and acquires a constant value. A similar physical situation arises when a football (initially kept at rest) is kicked and gets rebound from a rigid wall so that its speed gets reduced. Then, it passes from the player who has kicked it and ultimately stops after sometime.

b. From the given v-t graph it is clear that the sign of velocity changes and its magnitude decreases with a passage of time. This type of situation arises when a ball is dropped on the hard floor from a height. It strikes the floor with some velocity and upon rebound, its velocity decreases by a factor. This continues till the velocity of the ball eventually becomes zero.

c. From the given a-t graph it is clear that initially the body is moving with a certain uniform velocity. Its acceleration increases for a short interval of time, which again drops to zero. This shows that the body again starts moving with the same constant velocity. This type of physical situation arises when a hammer moving with a uniform velocity strikes a nail.

20. Figure gives the x-t plot of a particle executing one-dimensional simple harmonic motion.

(You will learn about this motion in more detail in Chapter14). Give the signs of position, velocity and acceleration variables of the particle at $t=0.3s,1.2s,-1.2s$.

Ans: Negative, Negative, Positive

Positive, Positive, Negative

Negative, Positive, Positive

When a particle executes simple harmonic motion (SHM), acceleration (a) is given by the relation: $a=-{{\omega }^{2}}x$

$\omega $ is the angular frequency ... 

i. \[~t\text{ }=\text{ }0.3\text{ }s\]

For this time interval, x is negative. Hence, the slope of the x-t plot will be negative. Thus, both position and velocity are negative. However, using equation (i), acceleration of the particle will be positive.

ii. \[~t\text{ }=1.2s\]

For this time interval, x is positive. Hence, the slope of the x-t plot will be positive. Thus, both position and velocity are positive. However, using equation (i), acceleration of the particle comes to be negative.

iii. \[\text{t }=-1.2s\]

For this time interval, x is negative. Hence, the slope of the x-t plot will be negative. Thus, both x and t are negative, the velocity comes to be positive. From equation (i), it can be interpreted that the acceleration of the particle will be positive.

21. Figure gives the x-t plot of a particle in one-dimensional motion. Three different equal intervals of time are shown. In which interval is the average speed greatest, and in which is it the least? Give the sign of average velocity for each interval.

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Ans: The average speed is greatest in interval 3 and least in interval 2. It is positive in intervals 1 & 2 and negative in interval 3.

The average speed of a particle shown in the x-t graph is given by the slope of the graph in a particular interval of time.

From the graph it is clear that the slope is maximum and minimum restively in intervals 3 and 2 respectively. Thus, the average speed of the particle is the greatest in interval 3 and is the least in interval 2. The sign of average velocity is positive in both intervals 1 and 2 as the slope is positive in these intervals. However, it is negative in interval 3 because the slope is negative in this interval.

22. Figure gives a speed-time graph of a particle in motion along a constant direction. Three equal intervals of time are shown. In which interval is the average acceleration greatest in magnitude? In which interval is the average speed greatest? Choosing the positive direction as the constant direction of motion, give the signs of v and a in the three intervals. What are the accelerations at the points A, B, C and D?

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Ans: From the graph given in the question,

Average acceleration is greatest in interval \[2\].

Average speed is greatest in intervals of $3$.

v is positive for intervals \[1,\text{ }2\], and $3$.

a is positive for intervals $1$ and $3$ and negative in interval $2$

\[a\text{ }=\text{ }0\] at A, B, C, D

Acceleration is calculated as the slope of the speed-time graph. In the given case, it is given by the slope of the speed-time graph within the given interval of time.

As the slope of the given speed-time graph is maximum in interval \[2\], average acceleration will be the greatest in this interval.

From the time-axis, height of the curve gives the average speed of the particle. It is clear that the height is the greatest in interval 3. Thus, average speed of the particle is the greatest in the interval 3.

For interval 1:

The slope of the speed-time graph is positive. Hence, acceleration is positive. Similarly, the speed of the particle is positive in this interval.

In interval 2:

As slope of the speed-time graph is negative, acceleration is negative in this interval. However, speed is positive because it is a scalar quantity.

In interval 3:

As the slope of the speed-time graph is zero, acceleration is zero in this interval.

However, here the particle acquires some uniform speed. It is positive in this interval.

Points A, B, C, and D are all parallel to the time-axis. Thus, the slope is zero at these points.

Therefore, at points A, B, C, and D, acceleration of the particle is zero.

23. A three-wheeler starts from rest, accelerates uniformly with \[1\text{ }m/{{s}^{2}}\] on a straight road for 10 s, and then moves with uniform velocity. Plot the distance covered by the vehicle during the nth second (n = 1,2,3....) versus n. What do you expect this plot to be during accelerated motion: a straight line or a parabola?

\[Initial\text{ }velocity=u=0m/s\]

\[Acceleration=a=1m/{{s}^{2}}\]

Distance covered by a body in nth second is given by the relation

${{s}_{n}}=u+\left( 2n-1 \right)a/2$

${{s}_{n}}=\left( 2n-1 \right)/2=n-1/2$ …… (1)

In this case, this relation shows that: ${{s}_{n}}$ linearly varies with n.

Now, substituting different values of n in equation (1), we get the following table:

The plot between n and will be a straight line shown in below figure:

24. A boy standing on a stationary lift (open from above) throws a ball upwards with the maximum initial speed he can, equal to \[49\text{ }m/s\]. How much time does the ball take to return to his hands? If the lift starts moving up with a uniform speed of $5m/s$ and the boy again throws the ball up with the maximum speed he can, how long does the ball take to return to his hands?

Initial velocity of the ball is \[u\text{ }=\text{ }49\text{ }m/s\].

Acceleration is $a=-g=-9.8m/{{s}^{2}}$.

Consider, 

When the lift was stationary, the boy throws the ball. Taking upward motion of the ball,

Final velocity, v of the ball becomes zero at the highest point.

From first equation of motion, time of ascent (t) is given as:

$t=\frac{v-u}{a}=\frac{-49}{-9.8}=5s$

However, the time of ascent is equal to the time of descent.

Thus, the total time taken by the ball to return to the boy’s hand is $5+5=10s$.

The lift was moving up with a uniform velocity of 5 m/s. Here, the relative velocity of the ball with respect to the boy remains the same i.e., \[49\text{ }m/s\]. Therefore, in this case also, the ball will return back to the boy’s hand in \[10\text{ }s\].

25. On a long horizontally moving belt (figure), a child runs to and fro with a speed \[9\text{ }km/hr\] (with respect to the belt) between his father and mother located 50 m apart on the moving belt. The belt moves with a speed of \[4\text{ }km\text{ }{{h}^{1}}\]. 

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For an observer on a stationary platform outside, what is the

a. speed of the child running in the direction of motion of the belt?

Ans: As the boy is running in the same direction of the motion of the belt, his speed (as observed by the stationary observer) will be:

\[{{v}_{bB\text{ }}}=\text{ }{{v}_{b}}\text{ }+\text{ }{{v}_{B}}\text{ }=\text{ }9\text{ }+\text{ }4\text{ }=\text{ }13\text{ }km/h\].

b. speed of the child running opposite to the direction of motion of the belt?

Ans: As the boy is running in the direction opposite to the direction of the motion of the belt, his speed (as observed by the stationary observer) can be obtained as:

\[{{v}_{bB\text{ }}}=\text{ }{{v}_{b}}\text{ }+\text{ }\left( -{{v}_{B}}\text{ } \right)=\text{ }9-4\text{ }=\text{ 5}km/h\]

c. time taken by the child in (a) and (b)? Which of the answers alter if motion is viewed by one of the parents?

Distance between the childs parents =50m

Since, both parents are standing on the moving belt, the speed of the child in either direction as observed by the parents will remain the same i.e., \[9\text{ }km/h\text{ }=\text{ }2.5\text{ }m/s\]. Thus, the time taken by the child to move towards one of his parents is \[50/2.5\text{ }=\text{ }20s\]. If the motion is viewed by any one of the parents, answers obtained in (a) and (b) get altered. This is because the child and his parents are standing on the same belt and hence, are equally affected by the motion of the belt. Therefore, for both parents (irrespective of the direction of motion) the speed of the child remains the same i.e., \[9\text{ }km/h\]. Therefore, it can be interpreted that the time taken by the child to reach any one of his parents remains unaltered.

26. Two stones are thrown up simultaneously from the edge of a cliff 200 m high with initial speeds of $15m/s$ and $30m/s$. Verify that the graph shown in figure correctly represents the time variation of the relative position of the second stone with respect to the first. Neglect air resistance and assume that the stones do not rebound after hitting the ground. Take \[g\text{ }=\text{ }10m/{{s}^{2}}\]. Give the equations for the linear and curved parts of the plot.

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Initial velocity ${{u}_{1}}=15m/s$.

Acceleration, $a=-g=-10m/{{s}^{2}}$.

Using the relation,

${{x}_{1}}={{x}_{0}}+{{u}_{1}}t+\left( 1/2 \right)a{{t}^{2}}$

Where, height of the cliff, ${{x}_{0}}=200m$.

${{x}_{1}}=200+15t-5{{t}^{2}}$ ….. (1)

When this stone hits the ground, ${{x}_{1}}=0m$.

$\therefore -5{{t}^{2}}+15t+200=0$

${{t}^{2}}-3t-40=0$

${{t}^{2}}-8t+5t-40=0$

$\left( t-8 \right)\left( t+5 \right)=0$

$\therefore t=8,-5$

Hence, $t=8s$.

For second stone:

Initial velocity, ${{u}_{2}}=30m/s$.

${{x}_{2}}={{x}_{0}}+{{u}_{2}}t+\left( 1/2 \right)a{{t}^{2}}$

${{x}_{2}}=200+30t-5{{t}^{2}}$ ….. (2)

When this stone hits the ground, ${{x}_{2}}=0m$.

$\therefore -5{{t}^{2}}+30t+200=0$

${{t}^{2}}-6t-40=0$

${{t}^{2}}-10t+4t-40=0$

$\left( t-10 \right)\left( t+4 \right)=0$

$\therefore t=10,-4$

Hence, $t=10s$.

Subtracting equations (i) and (ii), we get

${{x}_{2}}-{{x}_{1}}=\left( 200+30t-5{{t}^{2}} \right)-\left( 200+15t-5{{t}^{2}} \right)$

${{x}_{2}}-{{x}_{1}}=15t$ …… (3)

Equation (3) represents the linear path of both stones. Due to this linear relation between ${{x}_{2}}-{{x}_{1}}$ and t, the path remains a straight line till \[8\text{ }s\].

${{\left( {{x}_{2}}-{{x}_{1}} \right)}_{\max }}=15\times 8=120m$

This is in accordance with the given graph.

After 8 s, only second stone is in motion whose variation with time is given by the quadratic equation: ${{x}_{2}}-{{x}_{1}}=200+30t-5{{t}^{2}}$.

Hence, the equation of linear path is ${{x}_{2}}-{{x}_{1}}=15t$ and curved path is ${{x}_{2}}-{{x}_{1}}=200+30t-5{{t}^{2}}$.

27. The speed-time graph of a particle moving along a fixed direction is shown in figure. Obtain the distance traversed by the particle between $\left( a \right)\text{0s to 10s}$, (b) 2s to 6s. What is the average speed of the particle over the intervals in (a) and (b)?

seo images

Ans: From the graph given in the question:

(a) \[Distance\text{ }travelled\text{ }by\text{ }the\text{ }particle\text{ }=\text{ }Area\text{ }under\text{ }the\text{ }given\text{ }graph\]

$=\left( 1/2 \right)\times \left( 10-0 \right)\times \left( 12-0 \right)=60m$

\[Average\text{ }speed=Distance/Time=60/10=6m/s\]

(b) Let \[{{s}_{1}}\] and \[{{s}_{2}}\] be the distances covered by the particle between time \[t\text{ }=\text{ }2\text{ }s\] to \[5\text{ }s\] and \[t\text{ }=\text{ }5\text{ }s\] to \[6\text{ }s\] respectively.

Total distance (s) covered by the particle in time \[t\text{ }=\text{ }2\text{ }s\] to \[6\text{ }s\] will be:

$s={{s}_{1}}+{{s}_{2}}$ …… (i)

For distance \[{{s}_{1}}\]:

Let u′ be the velocity of the particle after \[2\text{ }s\] and a’ be the acceleration of the particle for $t=0\text{s to 5s}$.

Since the particle undergoes uniform acceleration in the interval $t=0\text{s to 5s}$, from first equation of motion, acceleration can be obtained as:

\[v\text{ }=\text{ }Final\text{ }velocity\text{ }of\text{ }the\text{ }particle\]

$a'=12/5=2.4m/{{s}^{2}}$

Again, from first equation of motion, we have

$=0+2.4\times 2=4.8m/s$

Distance travelled by the particle between time \[2\text{ }s\] and \[5\text{ }s\] i.e., in \[3\text{ }s\] will be:

${{s}_{1}}=u't+\left( 1/2 \right)a'{{t}^{2}}$

$=4.8\left( 3 \right)+\left( 1/2 \right)\times 2.4\times {{3}^{2}}=25.2m$ …… (ii)

For distance ${{s}_{2}}$,

Let a’’ be the acceleration of the particle between time $\text{t=5s and t=10s}$.

From first equation of motion,

$0=12+a''\times 5$

$a''=-2.4m/{{s}^{2}}$

Distance travelled by the particle in 1s (i.e., \[t\text{ }=\text{ 5}s\] to \[6s\])

${{s}_{2}}=u''t+\left( 1/2 \right)a''{{t}^{2}}$

$=12\times 1+\left( 1/2 \right)\left( -2.4 \right)\times {{\left( 1 \right)}^{2}}=10.8m$ …… (iii)

From equations (i), (ii), and (iii), we get:

\[\text{s=25}\text{.2+10}\text{.8=36m}\]

Hence, \[\text{Average speed = 36 / 4 = 9 m/s}\].

28. The velocity-time graph of a particle in one-dimensional motion is shown in Fig. 3.29. Which of the following formulae are correct for describing the motion of the particle over the time-interval \[{{t}_{1}}\text{ }to\text{ }{{t}_{2}}\]:

a. $x\left( {{t}_{2}} \right)=x\left( {{t}_{1}} \right)+v\left( {{t}_{1}} \right)\left( {{t}_{2}}-{{t}_{1}} \right)+\left( 1/2 \right)a{{\left( {{t}_{2}}-{{t}_{1}} \right)}^{2}}$

b. $v\left( {{t}_{2}} \right)=v\left( {{t}_{1}} \right)+a\left( {{t}_{2}}-{{t}_{1}} \right)$

c. ${{v}_{average}}=\left( x\left( {{t}_{2}} \right)-x\left( {{t}_{1}} \right) \right)/\left( {{t}_{2}}-{{t}_{1}} \right)$

d. ${{a}_{average}}=\left( v\left( {{t}_{2}} \right)-v\left( {{t}_{1}} \right) \right)/\left( {{t}_{2}}-{{t}_{1}} \right)$

e. $x\left( {{t}_{2}} \right)=x\left( {{t}_{1}} \right)+{{v}_{average}}\left( {{t}_{2}}-{{t}_{1}} \right)+\left( 1/2 \right){{a}_{average}}{{\left( {{t}_{2}}-{{t}_{1}} \right)}^{2}}$

where 

$x\left( {{t}_{2}} \right)-x\left( {{t}_{1}} \right)=\text{area under the v-t curve bounded by the t-axis and the dotted line as shown}$

seo images

Ans: The correct relations for the motion of the particle are (c), (d) and, (f). The given graph has a non-uniform slope. Thus, the relations given in (a), (b), and (e) cannot describe the motion of the particle. Only the relations given in (c), (d), and (f) are correct equations of motion.

NCERT Solutions for Class 11 Physics Chapter 3 PDF Download

Class 11 Physics NCERT Solutions Chapter 3 explains the technical measurement of various torques. All the answers that you see here have been written by experienced teachers in Physics with easy to understand methods and step-by-step approaches. Physics is the field that combines Science and Maths. In Chapter 3, Motion in a Straight Line, you will be solving lots of problems that require you to use both Physics and Maths combined. As a result, we have made a PDF for you that includes all the solutions, so it will be easier for students to see the answers even if they are offline.

In this chapter, you will study motion and the different kinds of motion. You will also read about concepts like path lengths and displacement. Additionally, you will learn about velocity and speed and the various numerical associated with them.

The chapter also talks about acceleration and how it's connected to speed and velocity. We then move on to kinematic equations and uniformly accelerated motion. We will also read about relative velocity and its derivations in this chapter.

If an object changes position with time, it is said to be in motion.

The path to the right of the origin is taken as positive and to the left is taken as negative when motion is in a straight line.

We read about the path of motion and displacement in this chapter.

We also read about the magnitude of the displacement.

The chapter contains various graphs and formulae to explain the displacement of motion.

We will study different kinds of motion, like rectilinear and uniform motions.

Displacement divided by time intervals is known as average velocity.

Average Speed - The total path length travelled in the total given time interval is known as average speed.

The chapter explains the relationship between velocity and speed.

You will be solving various numerical problems based on these concepts.

The chapter contains various in-text examples and questions of the students to solve.

The chapter also focuses on instantaneous velocity and speed and their derivations through numerical.

These numericals are also explained in the form of graphs.

You will study acceleration and its derivatives.

Solve various problems based on kinematic equations based on uniformly accelerated motion.

The chapter provides two methods to solve these equations for students to choose at your convenience.

The chapter concludes by giving a brief about relative velocity and its formulae.

NCERT Chapter 3 Marks Weightage

The maximum number of questions from this chapter is 2, and the total marks you can achieve in this chapter in your final term examination are five marks.

Benefits of Solving CBSE Class 11 Physics Chapter 3

When you have opted for non-medical, you are undoubtedly aiming to crack one of the world's toughest exams, which is the Joint Entrance Exam (JEE). Motion in a Straight Line looks like a simple topic, but it becomes the base for important problems that come in JEE exam. So when you are doing this chapter, you need to put your full concentration into it.

On the other hand, Motion in a Straight Line is one of the chapters which will also help you in your daily life. Whatever you have learned from this chapter, you can apply it in real life. This is something you can say about every chapter in Physics.

In addition to this, with the help of Physics, you can find out how the whole world works. From a small grain of sand to a massive universe and galaxies, you can find out how these things work.

Physics helps a child increase his critical thinking and make him think outside the box to solve the problem. Also, Physics can help you get a good job once you complete your degree.

Physics opens students to so many different opportunities in terms of career. You can be an astronaut and go to space. You can be a scientist and discover new stars in the sky. With the study of Physics, even the sky isn't the limit!

Moreover, Physics always has something new for you to discover. It is one of the few branches of study which never gets boring.

Lastly, it gives you a certain kind of challenge for which you need to be good in Maths to enjoy Physics at its full. All the different formulas, laws, and theorems that you see in Physics use Mathematics as its base.

NCERT Class 11 Physics Chapter wise Solutions - Free PDF Download

Chapter 1 - Physical World

Chapter 2 - Units and Measurement

Chapter 3 - Motion in a Straight Line

Chapter 4 - Motion in a Plane

Chapter 5 - Law of Motion

Chapter 6 - Work, Energy and Power

Chapter 7 - Systems of Particles and Rotational Motion

Chapter 8 - Gravitation

Chapter 9 - Mechanical Properties of Solids

Chapter 10 - Mechanical Properties of Fluids

Chapter 11 - Thermal Properties of Matter

Chapter 12 - Thermodynamics

Chapter 13 - Kinetic Theory

Chapter 14 - Oscillations

  • Chapter 15 - Waves

Topics Covered under NCERT Solution Class 11 Physics Chapter 3 Motion in a Straight Line

Introduction

Position, path length, and displacement

Average velocity and average speed

Instantaneous velocity and speed

Acceleration

Kinematic equations for uniformly accelerated motion

Relative velocity

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FAQs on NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line

1. If I'm not a Non-Medical Student, do I Still Need to Learn and Take Physics as One of the Subjects?

The answer to this question is both yes and no, you can opt for Physics even if you are not a non-medical student, but the only other branch which offers Physics as one of its subjects is medical. In that branch, you don't have maths as the main subject, but you can opt for maths as well. On the other hand, if you are from commerce or arts, you don't choose Physics. You can't opt for Physics as it's one of the core subjects and isn't easy. In the medical stream, you can opt for Physics.

2. If an Object has One Dimension Motion with a Positive Acceleration Value and Negative Velocity, is the Object Speeding up?

No, in this case, the object present in the starting point is not speeding up. As the velocity is negative, we can see that the particle is slowing down. This type of scenario happens only when the object is thrown upwards in the air. We can say the object is in acceleration if both the acceleration and the object's velocity have a positive value, or the object is falling from a height.

3. What are the contents of Chapter 3 of the Class 11 Physics textbook?

The theme of the chapter is Kinematics, motion in a straight line. Mechanics is a scientific term that refers to the study of the movement of physical objects. The chapter explains all the relevant terms in a simple and easy-to-understand language. The chapter distinguishes between rest and motion. You will also come across the terms position, distance, and displacement as well as the difference between speed and velocity. The chapter explains acceleration. The chapter also contains the units and mathematical representations.

4. What is the difference between distance and displacement according to Chapter 3 of the Class 11 Physics textbook?

Distance means the actual path traversed by the object whereas displacement refers to the difference between initial and final positions. The former is the scalar quantity while the latter is the vector quantity. The distance covered by an object is always positive; it can never be negative or zero. However, the displacement of an object can be either positive, negative, or even zero. The distance is dependent on the path traversed by the object but displacement is not dependent on the path.

5. What is the difference between speed and velocity Chapter 3 of the Class 11 Physics textbook?

Speed is the total path length covered by the object divided by the total time taken. Velocity is the change in position divided by time intervals. Speed is a scalar quantity. Velocity, however, is a vector quantity. Speed is always positive. Velocity, on the other hand, can be positive, negative, or zero. Speed is the time rate at which an object moves; speed is about how fast an object moves. Velocity is the rate and direction of the movement of an object.  

6. What are the types of motion mentioned in Chapter 3 of the Class 11 Physics textbook?

The motion refers to changes in the position or orientation of an object with the change in time. Motion can be of two types- Uniform motion or Non-Uniform motion. Uniform motion exists when the object completes equal distance in equal time intervals. Non-Uniform motion, on the other hand, exists when an object completes unequal distance in equal intervals of time. During a uniform motion, the velocity of the object remains the same. When an object undergoes non-uniform motion, the magnitude of the velocity increases or decreases with time.

7. How can previous years’ questions help in preparation of Motion in a straight line chapter of Class 11 Physics?

Previous years’ questions enable you to understand the pattern of the question and analyse the trend of the questions asked. These papers will give you an idea regarding the topics that you should invest more time and effort on. These question papers should also motivate you to make notes accordingly. The previous years’ question papers will lend a direction to your preparation and you will feel more prepared and confident on the day of the exam. These papers are available on the official website of Vedantu or the Vedantu app. All the resources are free of cost.

NCERT Solutions for Class 11 Physics

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CBSE Worksheets for Class 11 Physics

CBSE Worksheets for Class 11 Physics: One of the best teaching strategies employed in most classrooms today is Worksheets. CBSE Class 11 Physics Worksheet for students has been used by teachers & students to develop logical, lingual, analytical, and problem-solving capabilities. So in order to help you with that, we at WorksheetsBuddy have come up with Kendriya Vidyalaya Class 11 Physics Worksheets for the students of Class 11. All our CBSE NCERT Class 11 Physics practice worksheets are designed for helping students to understand various topics, practice skills and improve their subject knowledge which in turn helps students to improve their academic performance. These chapter wise test papers for Class 11 Physics will be useful to test your conceptual understanding.

Board: Central Board of Secondary Education(www.cbse.nic.in) Subject: Class 11 Physics Number of Worksheets: 103

CBSE Class 11 Physics Worksheets PDF

All the CBSE Worksheets for Class 11 Physics provided in this page are provided for free which can be downloaded by students, teachers as well as by parents. We have covered all the Class 11 Physics important questions and answers in the worksheets which are included in CBSE NCERT Syllabus. Just click on the following link and download the CBSE Class 11 Physics Worksheet. CBSE Worksheets for Class 11 Physics can also use like assignments for Class 11 Physics students.

  • CBSE Worksheets for Class 11 Physics Gravitation Assignment 1
  • CBSE Worksheets for Class 11 Physics Gravitation Assignment 2
  • CBSE Worksheets for Class 11 Physics Kinetic Theory Assignment 1
  • CBSE Worksheets for Class 11 Physics Kinetic Theory Assignment 2
  • CBSE Worksheets for Class 11 Physics Laws of Motion Assignment 1
  • CBSE Worksheets for Class 11 Physics Laws of Motion Assignment 2
  • CBSE Worksheets for Class 11 Physics Laws of Motion Assignment 3
  • CBSE Worksheets for Class 11 Physics Mechanical Properties of Fluids Assignment 1
  • CBSE Worksheets for Class 11 Physics Mechanical Properties of Fluids Assignment 2
  • CBSE Worksheets for Class 11 Physics Mechanical Properties of Fluids Assignment 3
  • CBSE Worksheets for Class 11 Physics Mechanical Properties of Fluids Assignment 4
  • CBSE Worksheets for Class 11 Physics Mechanical Properties of Fluids Assignment 5
  • CBSE Worksheets for Class 11 Physics Mechanical Properties of Solids Assignment 1
  • CBSE Worksheets for Class 11 Physics Mechanical Properties of Solids Assignment 2
  • CBSE Worksheets for Class 11 Physics Motion in a Plane Assignment 1
  • CBSE Worksheets for Class 11 Physics Motion in a Plane Assignment 2
  • CBSE Worksheets for Class 11 Physics Motion in a Plane Assignment 3
  • CBSE Worksheets for Class 11 Physics Motion in a Straight Line Assignment 1
  • CBSE Worksheets for Class 11 Physics Motion in a Straight Line Assignment 2
  • CBSE Worksheets for Class 11 Physics Oscillations Assignment 1
  • CBSE Worksheets for Class 11 Physics Oscillations Assignment 2
  • CBSE Worksheets for Class 11 Physics Oscillations Assignment 3
  • CBSE Worksheets for Class 11 Physics Physical World Assignment 1
  • CBSE Worksheets for Class 11 Physics Physical World Assignment 2
  • CBSE Worksheets for Class 11 Physics Physical World Assignment 3
  • CBSE Worksheets for Class 11 Physics Physical World Assignment 4
  • CBSE Worksheets for Class 11 Physics System of Particle and Rigid Body Assignment 1
  • CBSE Worksheets for Class 11 Physics System of Particle and Rigid Body Assignment 2
  • CBSE Worksheets for Class 11 Physics Systems of Particles and Rotational Motion Assignment 1
  • CBSE Worksheets for Class 11 Physics Systems of Particles and Rotational Motion Assignment 2
  • CBSE Worksheets for Class 11 Physics Systems of Particles and Rotational Motion Assignment 3
  • CBSE Worksheets for Class 11 Physics Thermal Properties of Fluids Assignment 1
  • CBSE Worksheets for Class 11 Physics Thermal Properties of Fluids Assignment 2
  • CBSE Worksheets for Class 11 Physics Thermal Properties of Fluids Assignment 3
  • CBSE Worksheets for Class 11 Physics Thermal Properties of Fluids Assignment 4
  • CBSE Worksheets for Class 11 Physics Thermodynamics Assignment 1
  • CBSE Worksheets for Class 11 Physics Thermodynamics Assignment 2
  • CBSE Worksheets for Class 11 Physics Units and Measurement Assignment 1
  • CBSE Worksheets for Class 11 Physics Units and Measurement Assignment 2
  • CBSE Worksheets for Class 11 Physics Units and Measurement Assignment 3
  • CBSE Worksheets for Class 11 Physics Waves Assignment 1
  • CBSE Worksheets for Class 11 Physics Waves Assignment 2
  • CBSE Worksheets for Class 11 Physics Waves Assignment 3
  • CBSE Worksheets for Class 11 Physics Waves Assignment 4
  • CBSE Worksheets for Class 11 Physics Waves Assignment 5
  • CBSE Worksheets for Class 11 Physics Work Energy and Power Assignment 1
  • CBSE Worksheets for Class 11 Physics Work Energy and Power Assignment 2
  • CBSE Worksheets for Class 11 Physics Work Energy and Power Assignment 3
  • CBSE Worksheets for Class 11 Physics Work Energy and Power Assignment 4
  • CBSE Worksheets for Class 11 Physics Work Energy and Power Assignment 5
  • CBSE Worksheets for Class 11 Physics Motion In A Straight Line Assignment 1
  • CBSE Worksheets for Class 11 Physics Motion In A Straight Line Assignment 2
  • CBSE Worksheets for Class 11 Physics Motion In A Straight Line Assignment 3
  • CBSE Worksheets for Class 11 Physics System of Particles Assignment 1
  • CBSE Worksheets for Class 11 Physics System of Particles Assignment 2
  • CBSE Worksheets for Class 11 Physics System Of Particles And Rotational Motion Assignment
  • CBSE Worksheets for Class 11 Physics Thermal Properties of Matter Assignment 1
  • CBSE Worksheets for Class 11 Physics Thermal Properties of Matter Assignment 2
  • CBSE Worksheets for Class 11 Physics Unit and Measurements Assignment 1
  • CBSE Worksheets for Class 11 Physics Unit and Measurements Assignment 2
  • CBSE Worksheets for Class 11 Physics Units And Measurement Assignment
  • CBSE Worksheets for Class 11 Physics Assignment 1
  • CBSE Worksheets for Class 11 Physics Assignment 2
  • CBSE Worksheets for Class 11 Physics Assignment 3
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Advantages of CBSE Class 11 Physics Worksheets

  • By practising NCERT CBSE Class 11 Physics Worksheet , students can improve their problem solving skills.
  • Helps to develop the subject knowledge in a simple, fun and interactive way.
  • No need for tuition or attend extra classes if students practise on worksheets daily.
  • Working on CBSE worksheets are time-saving.
  • Helps students to promote hands-on learning.
  • One of the helpful resources used in classroom revision.
  • CBSE Class 11 Physics Workbook Helps to improve subject-knowledge.
  • CBSE Class 11 Physics Worksheets encourages classroom activities.

Worksheets of CBSE Class 11 Physics are devised by experts of WorksheetsBuddy experts who have great experience and expertise in teaching Maths. So practising these worksheets will promote students problem-solving skills and subject knowledge in an interactive method. Students can also download CBSE Class 11 Physics Chapter wise question bank pdf and access it anytime, anywhere for free. Browse further to download free CBSE Class 11 Physics Worksheets PDF .

Now that you are provided all the necessary information regarding CBSE Class 11 Physics Worksheet and we hope this detailed article is helpful. So Students who are preparing for the exams must need to have great solving skills. And in order to have these skills, one must practice enough of Class 11 Physics revision worksheets . And more importantly, students should need to follow through the worksheets after completing their syllabus.  Working on CBSE Class 11 Physics Worksheets will be a great help to secure good marks in the examination. So start working on Class 11 Physics Worksheets to secure good score.

CBSE Worksheets For Class 11

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Class 11 physics notes, numerical problems, important mcqs.

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Assignments For Class 11 Physics

Assignments for Class 11 Physics have been developed for Standard 11 students based on the latest syllabus and textbooks applicable in CBSE, NCERT and KVS schools. Parents and students can download the full collection of class assignments for class 11 Physics from our website as we have provided all topic wise assignments free in PDF format which can be downloaded easily. Students are recommended to do these assignments daily by taking printouts and going through the questions and answers for Grade 11 Physics. You should try to do these test assignments on a daily basis so that you are able to understand the concepts and details of each chapter in your Physics book and get good marks in class 11 exams.

Assignments for Class 11 Physics as per CBSE NCERT pattern

All students studying in Grade 11 Physics should download the assignments provided here and use them for their daily routine practice. This will help them to get better grades in Physics exam for standard 11. We have made sure that all topics given in your textbook for Physics which is suggested in Class 11 have been covered ad we have made assignments and test papers for all topics which your teacher has been teaching in your class. All chapter wise assignments have been made by our teachers after full research of each important topic in the textbooks so that you have enough questions and their solutions to help them practice so that they are able to get full practice and understanding of all important topics. Our teachers at https://www.assignmentsbag.com have made sure that all test papers have been designed as per CBSE, NCERT and KVS syllabus and examination pattern. These question banks have been recommended in various schools and have supported many students to practice and further enhance their scores in school and have also assisted them to appear in other school level tests and examinations. Its easy to take print of thee assignments as all are available in PDF format.

Some advantages of Free Assignments for Class 11 Physics

  • Solving Assignments for Physics Class 11 helps to further enhance understanding of the topics given in your text book which will help you to get better marks
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  • You will be able to understand the type of questions which are expected in your Physics class test
  • You will be able to revise all topics given in the ebook for Class 11 Physics as all questions have been provided in the question banks
  • NCERT Class 11 Physics Workbooks will surely help you to make your concepts stronger and better than anyone else in your class.
  • Parents will be able to take print out of the assignments and give to their child easily.

All free Printable practice assignments are in PDF single lick download format and have been prepared by Class 11 Physics teachers after full study of all topics which have been given in each chapter so that the students are able to take complete benefit from the worksheets. The Chapter wise question bank and revision assignments can be accessed free and anywhere. Go ahead and click on the links above to download free CBSE Class 11 Physics Assignments PDF.

Assignments For Class 11 Physics

You can download free assignments for class 11 Physics from https://www.assignmentsbag.com

You can get free PDF downloadable assignments for Grade 11 Physics from our website which has been developed by teachers after doing extensive research in each topic.

On our website we have provided assignments for all subjects in Grade 11, all topic wise test sheets have been provided in a logical manner so that you can scroll through the topics and download the worksheet that you want.

You can easily get question banks, topic wise notes and questions and other useful study material from https://www.assignmentsbag.com without any charge

Yes all test papers for Physics Class 11 are available for free, no charge has been put so that the students can benefit from it. And offcourse all is available for download in PDF format and with a single click you can download all assignments.

https://www.assignmentsbag.com is the best portal to download all assignments for all classes without any charges.

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  1. Class 11 Physics Assignments Download Pdf with Solutions

    All Assignments and test sheets have been prepared by expert teachers as per the latest Syllabus in Physics Class 11. Students can click on the links below and download all Pdf Assignments for Physics class 11 for free. All latest Kendriya Vidyalaya Class 11 Physics Assignments with Answers and test papers are given below.

  2. Assignment 3.4

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    on August 21, 2023, 6:38 AM. NCERT Solutions for Class 11 Physics in Hindi and English Medium PDF format are available to download updated for new academic session 2024-25. CBSE Class 11 Physics NCERT Solutions are a set of comprehensive and detailed answers, explanations, and solutions for the exercises and problems presented in the Class 11 ...

  7. NCERT Solutions for Class 11 Physics Chapter 4 Motion in A Plane

    NCERT Solutions Class 11 Physics Chapter 4 - Free PDF Download *According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 3. NCERT Solutions for Class 11 Physics Chapter 4 Motion in a Plane is one of the important study materials for Class 11 students as it is one of the most scoring chapters in kinematics. Students must try to understand each and every topic in a ...

  8. NCERT Solutions for Class 11 Physics (Updated for 2023

    NCERT Solutions for Class 11 Physics (Chapter-wise) Chapter 1: Units and Measurements. Chapter 2: Motion in a Straight Line. Chapter 3: Motion in a Plane. Chapter 4: Laws of Motion. Chapter 5: Work, Energy, and Power. Chapter 6: System of Particles and Rotational Motion. Chapter 7: Gravitation.

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  10. NCERT Solutions for Class 11 Physics Chapter 3 Free PDF Download

    NCERT Solutions for Class 11 Physics Chapter 3 deals with Motion in Straight Line. First of all, motion refers to a change in position of an object. Furthermore, this change is with respect to the surroundings of the object. Also, this change takes place in a given interval of time. Motion is certainly common to everything in the Universe.

  11. NCERT Solutions for Class 11 Physics Chapter 3 Motion in a ...

    These papers are available on the official website of Vedantu or the Vedantu app. All the resources are free of cost. Download NCERT Solutions for Class 11 Physics Chapter 3 - Motion in a Straight Line (Updated for 2023-24) in a PDF format for free and ace your final examination.

  12. Class 11 Physics Notes FBISE & KPK Board

    Chapter 3 Assignments (complete) Chapter 3 Conceptual Questions (complete) Chapter 3 Numerical Questions (complete) 11th Class Physics Chapter 4 Work & Energy. Chapter 4 Theory (complete) Chapter 4 Conceptual Questions (complete) 11th Class Physics Chapter 5 Rotational & Circular Motion. Chapter 5 Theory (complete) Chapter 5 Conceptual ...

  13. CBSE Worksheets for Class 11 Physics

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  14. Physics notes for class 11

    Chapter 11: Thermal Properties of Matter. This chapter is about Thermal Properties of Matter like Thermal Expansion ,temperature,Specific Heat Capacity.An introduction on Calorimetry & Change of phases & Latent Heat. Then it talks about various mode of Heat transfer like Thermal conduction, Convection & Radiation. Notes.

  15. Physics 11

    6. 20 Feb 2024. (Tue) Notes: Graphs of Motion (Velocity vs. Time) Worksheet: Graphs of Motion II ( solutions) Assignment: Kinematics Video Analysis due next class (print and bring to class) Lab: Acceleration due to Gravity Lab complete Introduction pre-lab questions for next class. In-Class Questions.

  16. Class 11 Physics Notes For FBISE

    Class XI Physics Notes Class 11 Physics notes according to FBISE syllabus. Contains solved exercises, review questions, MCQs, important questions and chapter overview. Class 11 Physics Notes Chapter 1 - Measurements Notes Exercise Numerical Problems Important MCQs Chapter 2 - Vectors and Equilibrium Notes Exercise Numerical Problems Important MCQs Chapter 3 - Motion and Force […]

  17. Solved Assignments Chapter 4 Physics Class 11 Forces and ...

    Assignment 4.1, 4.2 and 4.3 | Chapter 4 Work and Energy | Class 11 Physics | FBISE | Study With Me=====Chapter Wise All Assignments=====Chapter 1 https://you...

  18. Assignments For Class 11 Physics

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  19. Class 11 Physics Ch.4 Work and Energy

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    Instructor: Ms. Maimoona Altaf (MPhil Physics)Dear Students, in this video you will learn about how to solve assignment 2.3 of the physics grade 11 new book...