lesson 13 homework answer key 5th grade

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Eureka Math Grade 5 Module 4 Lesson 13 Answer Key

Engage ny eureka math 5th grade module 4 lesson 13 answer key, eureka math grade 5 module 4 lesson 13 problem set answer key.

Solve. Draw a rectangular fraction model to show your thinking. Then, write a multiplication sentence. The first one has been done for you.

b. Half of \(\frac{1}{3}\) pan of brownies = _____ pan of brownies.

Answer: \(\frac{1}{6}\) pan of brownies.

Explanation: Given that there is half of \(\frac{1}{3}\) pan of brownies which is \(\frac{1}{2}\) × \(\frac{1}{3}\) = \(\frac{1}{6}\) pan of brownies.

c. A fourth of \(\frac{1}{3}\) pan of brownies = _____ pan of brownies.

Answer: \(\frac{1}{12}\) pan of brownies.

Explanation: Given that there is half of \(\frac{1}{3}\) pan of brownies which is \(\frac{1}{4}\) × \(\frac{1}{3}\) = \(\frac{1}{12}\) pan of brownies.

d. \(\frac{1}{4}\) of \(\frac{1}{4}\)

Answer: \(\frac{1}{16}\).

Explanation: Given that \(\frac{1}{4}\) of \(\frac{1}{4}\) which is \(\frac{1}{4}\) × \(\frac{1}{4}\) = \(\frac{1}{16}\).

e. \(\frac{1}{2}\) of \(\frac{1}{6}\)

Answer: \(\frac{1}{12}\).

Explanation: Given that \(\frac{1}{2}\) of \(\frac{1}{6}\) which is \(\frac{1}{2}\) × \(\frac{1}{6}\) = \(\frac{1}{12}\).

Question 2. Draw rectangular fraction models of 3 × \(\frac{1}{4}\) and \(\frac{1}{3}\) × \(\frac{1}{4}\). Compare multiplying a number by 3 and by 1 third.

Answer: \(\frac{3}{4}\) > \(\frac{1}{12}\).

Question 3. \(\frac{1}{2}\) of Ila’s workspace is covered in paper. \(\frac{1}{3}\) of the paper is covered in yellow sticky notes. What fraction of Ila’s workspace is covered in yellow sticky notes? Draw a picture to support your answer.

Answer: \(\frac{1}{6}\)

Explanation: Given that \(\frac{1}{2}\) of Ila’s workspace is covered in paper and \(\frac{1}{3}\) of the paper is covered in yellow sticky notes, so the fraction of Ila’s workspace is covered in yellow sticky notes is \(\frac{1}{2}\) × \(\frac{1}{3}\) which is \(\frac{1}{6}\).

Question 4. A marching band is rehearsing in rectangular formation. \(\frac{1}{5}\) of the marching band members play percussion instruments. \(\frac{1}{2}\) of the percussionists play the snare drum. What fraction of all the band members play the snare drum?

Answer: The fraction of all the band members who play the snare drum is \(\frac{1}{10}\).

Explanation: Given that a \(\frac{1}{5}\) of the marching band members play percussion instruments and \(\frac{1}{2}\) of the percussionists play the snare drum, so the fraction of all the band members play the snare drum is \(\frac{1}{2}\) of \(\frac{1}{5}\) which is \(\frac{1}{2}\) × \(\frac{1}{5}\) = \(\frac{1}{10}\).

Question 5. Marie is designing a bedspread for her grandson’s new bedroom. \(\frac{2}{3}\) of the bedspread is covered in race cars, and the rest is striped. \(\frac{1}{4}\) of the stripes are red. What fraction of the bedspread is covered in red stripes?

Answer: The fraction of the bedspread is covered in red stripes is \(\frac{1}{12}\).

Explanation: Given that \(\frac{2}{3}\) of the bedspread is covered in race cars, and the rest is stripped and \(\frac{1}{4}\) of the stripes are red. The striped bedspread would be 1 – \(\frac{2}{3}\) which is \(\frac{1}{3}\). So the fraction of the bedspread is covered in red stripes is \(\frac{1}{3}\) × \(\frac{1}{4}\) which is \(\frac{1}{12}\).

Eureka Math Grade 5 Module 4 Lesson 13 Exit Ticket Answer Key

Question 1. Solve. Draw a rectangular fraction model, and write a number sentence to show your thinking.

\(\frac{1}{3}\) × \(\frac{1}{3}\) =

Answer: \(\frac{1}{9}\).

Explanation: Given that \(\frac{1}{3}\) × \(\frac{1}{3}\) which is \(\frac{1}{9}\).

Question 2. Ms. Sheppard cuts \(\frac{1}{2}\) of a piece of construction paper. She uses \(\frac{1}{6}\) of the piece to make a flower. What fraction of the sheet of paper does she use to make the flower?

Answer: The fraction of the sheet of paper does she use to make the flower is \(\frac{1}{12}\).

Explanation: Given that Ms. Sheppard cuts \(\frac{1}{2}\) of a piece of construction paper and she uses \(\frac{1}{6}\) of the piece to make a flower, so the fraction of the sheet of paper does she use to make the flower is \(\frac{1}{2}\) × \(\frac{1}{6}\) which is \(\frac{1}{12}\).

Eureka Math Grade 5 Module 4 Lesson 13 Homework Answer Key

Solve. Draw a rectangular fraction model to show your thinking.

a. Half of \(\frac{1}{2}\) cake = _____ cake.

Answer: \(\frac{1}{4}\).

Explanation: Given that half of \(\frac{1}{2}\) cake which is \(\frac{1}{2}\) × \(\frac{1}{2}\) = \(\frac{1}{4}\).

b. One-third of \(\frac{1}{2}\) cake = _____ cake.

Answer: \(\frac{1}{6}\).

Explanation: Given that One-third of \(\frac{1}{2}\) cake which is \(\frac{1}{3}\) × \(\frac{1}{2}\) = \(\frac{1}{6}\).

c. \(\frac{1}{4}\) of \(\frac{1}{2}\)

Answer: \(\frac{1}{8}\).

Explanation: Given that latex]\frac{1}{4}[/latex] of \(\frac{1}{2}\) which is latex]\frac{1}{4}[/latex] × \(\frac{1}{2}\) = \(\frac{1}{8}\).

d. \(\frac{1}{2}\) × \(\frac{1}{5}\)

Answer: \(\frac{1}{10}\).

Explanation: Given that latex]\frac{1}{2}[/latex] of \(\frac{1}{5}\) which is latex]\frac{1}{2}[/latex] × \(\frac{1}{5}\) = \(\frac{1}{10}\).

e. \(\frac{1}{3}\) × \(\frac{1}{3}\)

Explanation: Given that latex]\frac{1}{3}[/latex] of \(\frac{1}{3}\) which is latex]\frac{1}{3}[/latex] × \(\frac{1}{3}\) = \(\frac{1}{9}\).

f. \(\frac{1}{4}\) × \(\frac{1}{3}\)

Explanation: Given that latex]\frac{1}{4}[/latex] of \(\frac{1}{3}\) which is latex]\frac{1}{4}[/latex] × \(\frac{1}{3}\) = \(\frac{1}{12}\).

Question 2. Noah mows \(\frac{1}{2}\) of his property and leaves the rest wild. He decides to use \(\frac{1}{5}\) of the wild area for a vegetable garden. What fraction of the property is used for the garden? Draw a picture to support your answer.

Answer: The fraction of the property is used for the garden is \(\frac{1}{10}\).

Explanation: Given that Noah mows \(\frac{1}{2}\) of his property and leaves the rest wild and he decides to use \(\frac{1}{5}\) of the wild area for a vegetable garden, so the fraction of the property is used for the garden is \(\frac{1}{2}\) × \(\frac{1}{5}\) which is \(\frac{1}{2}\) × \(\frac{1}{5}\) = \(\frac{1}{10}\).

Question 3. Fawn plants \(\frac{2}{3}\) of the garden with vegetables. Her son plants the remainder of the garden. He decides to use \(\frac{1}{2}\) of his space to plant flowers, and in the rest, he plants herbs. What fraction of the entire garden is planted in flowers? Draw a picture to support your answer.

Answer: The fraction of the entire garden is planted in flowers is \(\frac{1}{6}\).

Explanation: Given that fawn plants \(\frac{2}{3}\) of the garden with vegetables and her son plants the remainder of the garden and he decides to use \(\frac{1}{2}\) of his space to plant flowers, and in the rest, he plants herbs. So her son gets \(\frac{2}{3}\) × \(\frac{1}{2}\) which is \(\frac{1}{3}\). So the fraction of the entire garden is planted in flowers is \(\frac{1}{2}\) × \(\frac{1}{3}\) which is \(\frac{1}{6}\).

Question 4. Diego eats \(\frac{1}{5}\) of a loaf of bread each day. On Tuesday, Diego eats \(\frac{1}{4}\) of the day’s portion before lunch. What fraction of the whole loaf does Diego eat before lunch on Tuesday? Draw a rectangular fraction model to support your thinking.

Answer: The fraction of the whole loaf does Diego eat before lunch on Tuesday is \(\frac{1}{20}\).

Explanation: Given that Diego eats \(\frac{1}{5}\) of a loaf of bread each day and on tuesday, Diego eats \(\frac{1}{4}\) of the day’s portion before lunch. So the fraction of the whole loaf does Diego eat before lunch on Tuesday is \(\frac{1}{5}\) × \(\frac{1}{4}\) which is \(\frac{1}{20}\).

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Eureka Math Grade 5 Module 5 Lesson 13

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Some of the worksheets for this concept are Grade 5 module 1, Grade 3 book of s s, Grade 2 book of s s, Grade 5 module 3, Grade 5 module 3 application problems engageny eureka math, A story of ratios, Eureka math homework helper 20152016 grade 5 module 2, Grade 4 module 3.

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1. GRADE 5 MODULE 1

2. grade 3 book of sprints, 3. grade 2 book of sprints, 4. grade 5 module 3, 5. grade 5 module 3 application problems engageny eureka math ..., 6. a story of ratios, 7. eureka math homework helper 20152016 grade 5 module 2, 8. grade 4 module 3.

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Eureka Math Grade 5 Module 5 Lesson 13 Answer Key

Engage ny eureka math 5th grade module 5 lesson 13 answer key, eureka math grade 5 module 5 lesson 13 problem set answer key.

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{5}{4}\) km × \(\frac{12}{5}\) km b. 16\(\frac{1}{2}\) m × 4\(\frac{1}{5}\) m c. 4\(\frac{1}{3}\) yd × 5\(\frac{2}{3}\) yd d. \(\frac{7}{8}\) mi × 4\(\frac{1}{3}\) mi Answer:

Therefore, 3 square kilometres

16 1/2 x 4 1/5

=  (16 x 4) + ( 16 x 1/5) + ( 4 x 1/2) x ( 1/2 x 1/5 )

= 64 + 16/5 + 2 + 1/10

Therefore, 69 3/10 square metres

4 1/3 x 5 2/3

4 x 5 + 4 x 2/3 + 5 x 1/3 + 1/3 x 2/3

= 20 +8/3 +5/3 +2/9

Therefore, 24 5/9 square yards

d.7/8 mi x 4 1/3 mi

= (7/8 x 4) + (7/8 x 1/3)

= 84/24 + 7/24

Therefore, 3 19/24 sq. mi

Question 2. Julie is cutting rectangles out of fabric to make a quilt. If the rectangles are 2\(\frac{3}{5}\) inches wide and 3\(\frac{2}{3}\) inches long, what is the area of four such rectangles? Answer:

Given, the measurements of the rectangles =

2 3/5 x 3 2/3

=( 2 x 3 ) + (2 x 2/3) + (3 x 3/5) + ( 3/5 x 2/3)

= 6 + 4/3 + 9/5 + 6/15

=6 + 3 8/15

= 9 8/15 square inches

Now, number of rectangles = 4

So, 4 x 9 8/15

= 36 + 2 2/15

Therefore, 38 2/15 square inches.

Given, the measurements of the lawn = 24 1/2 yd by 24 1/2 yd

The area of the lawn =

24 1/2 x 24 1/2

= (24 x 24 ) + (24 x 1/2 ) + (24 x 1/2) + ( 1/2 x 1/2)

= 576 + 12 +12 +1/4

=600 1/4 square yards

The area of the pool house = 16 square yards

The area of the pool =

7 1/2 yd x 2 1/2 yd

= 14 + 3 1/2 + 1 + 1/4

The area of sidewalk = 1 yd x 3 yd = 3 yd

Now, the amount of sod Howard needs to buy =

6001/4 – 16 – 18 3/4 – 3

= 581 1/4 – 18 2/4

= 580 5/4 – 18 3/4

= 562 1/2 square yards

Therefore, Howard need 562 1/2 square yards of sod.

Eureka Math Grade 5 Module 5 Lesson 13 Exit Ticket Answer Key

Find the area of the following rectangles. Draw an area model if it helps you. Question 1. \(\frac{7}{2}\) mm × \(\frac{14}{5}\) mm Answer:

7/2 mm x 4/5 mm

= 7/2 x 4/5

= 9 4/5 square mm

Question 2. 5\(\frac{7}{8}\) km × \(\frac{18}{4}\) km Answer:

5/8 km x 18/4 km

= 5/8 x 18/4

= 26 7/16 square kilometres.

Eureka Math Grade 5 Module 5 Lesson 13 Homework Answer Key

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{8}{3}\) cm × \(\frac{24}{4}\) cm b. \(\frac{32}{5}\) ft × 3\(\frac{3}{8}\) ft c. 5\(\frac{4}{6}\) in × 4 \(\frac{3}{5}\) in d. \(\frac{5}{7}\) m × 6\(\frac{3}{5}\) m Answer:

8/3 cm x 24/4 cm

= 8/3 x 24/4

Therefore, 16 square centimetres

32/5 feet x 3 3/8

32/5 = 6 2/5

= 18 +  18/8 + 6/5 + 9/40

=  18 + 2 1/4 + 1 1/5 + 9/40

= 21 + 27/40

Therefore, 21 27/40 square feet

5 4/6 feet x 4 3/5 feet

( 5 x 4 ) + ( 5 x 3/5) + (4/6 x 4 ) + ( 4/6 x 3/5)

= 20 + 15/5 + 16/6 + 12/30

=20 + 3 + 8/3 + 2/5

= 25 +20/30 + 12/30

Therefore, 26 1/15 square inches

5/7 m x 6 3/5 m

= 5/7 x 6 3/5

=  30/7 + 15/35

= 4 2/7 + 3/7

Therefore, 4 5/7 square inches

Question 2. Chris is making a tabletop from some leftover tiles. He has 9 tiles that measure 3\(\frac{1}{8}\) inches long and 2\(\frac{3}{4}\) inches wide. What is the greatest area he can cover with these tiles? Answer:

Given, the measurements of the tiles =

3 1/8 x 2 3/4

= 6 + 9/4 + 2/8 + 3/32

= 6 +2 1/4 + 1/4 + 3/32

Now, the greatest area he can cover with 9 tiles=

= 9 x 8 19/32

= 72 + 191/32

= 72 +5 11/32

= 77 11/32 square inches.

Therefore, the greatest area he can cover = 77 11/32.

31 7/8 x 19 1/2

= ( 31 x 19) + ( 31 x 1/2 ) + (19 x 7/8 ) + ( 7/8 x 1/2)

= 589 + 31/2 + 133/8 + 7/16

= 589 + 15 1/2 + 16 5/8 + 7/16

= 620 + 1/2 + 5/8 + 7/16

= 630 + 8/16 + 10/16 + 7/16

= 620 25/16 square feet.

b. 13 3/5 feet x 11 3/4 feet

= ( 13 x 11) + ( 13 x 3/4 ) + (3/5 x 11 ) + ( 3/5 x 3/4)

= 143 + 9 3/4 + 6 3/5 + 9/20

=158 + 15/20 + 12/20 + 9/20

= 159 16/20

= 159 4/5 square feet

= 36 + 36/4

= 45 square feet

= 34 + 17/2

= 34 + 8 1/2

= 42 1/2 square feet

159 4/5 + 45 + 42 1/2

= 247 3/10 square feet

So, 621 9/16 – 247 3/10

= 384 21/80

Therefore, 384 21/80 square feet of carpeting is needed.

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