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A Simple, Fast, and Intelligent AI Homework Helper

A Simple, Fast, and Intelligent AI Homework Helper

A Simple, Fast, and Intelligent AI Homework Helper

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How does HomeworkAI handle problems with multiple solution methods?

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Listen: we know homework isn’t fun, but it is a good way to reinforce the ideas and concepts you’ve learned in class. But what if you’re really struggling with your homework assignments?

If you’ve looked online for a little extra help with your take-home assignments, you’ve probably stumbled across websites claiming to provide the homework help and answers students need to succeed . But can homework help sites really make a difference? And if so, which are the best homework help websites you can use? 

Below, we answer these questions and more about homework help websites–free and paid. We’ll go over: 

  • The basics of homework help websites
  • The cost of homework help websites 
  • The five best homework websites out there 
  • The pros and cons of using these websites for homework help 
  • The line between “learning” and “cheating” when using online homework help 
  • Tips for getting the most out of a homework help website

So let’s get started! 

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The Basics About Homework Help Websites–Free and Paid

Homework help websites are designed to help you complete your homework assignments, plain and simple. 

What Makes a Homework Help Site Worth Using

Most of the best sites allow users to ask questions and then provide an answer (or multiple possible answers) and explanation in seconds. In some instances, you can even send a photo of a particular assignment or problem instead of typing the whole thing out! 

Homework help sites also offer more than just help answering homework questions. Common services provided are Q&A with experts, educational videos, lectures, practice tests and quizzes, learning modules, math solving tools, and proofreading help. Homework help sites can also provide textbook solutions (i.e. answers to problems in tons of different textbooks your school might be using), one-on-one tutoring, and peer-to-peer platforms that allow you to discuss subjects you’re learning about with your fellow students. 

And best of all, nearly all of them offer their services 24/7, including tutoring! 

What You Should Should Look Out For

When it comes to homework help, there are lots–and we mean lots –of scam sites out there willing to prey on desperate students. Before you sign up for any service, make sure you read reviews to ensure you’re working with a legitimate company. 

A word to the wise: the more a company advertises help that veers into the territory of cheating, the more likely it is to be a scam. The best homework help websites are going to help you learn the concepts you’ll need to successfully complete your homework on your own. (We’ll go over the difference between “homework help” and “cheating” a little later!) 

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You don't need a golden piggy bank to use homework help websites. Some provide low or no cost help for students like you!

How Expensive Are the Best Homework Help Websites?

First of all, just because a homework help site costs money doesn’t mean it’s a good service. Likewise, just because a homework help website is free doesn’t mean the help isn’t high quality. To find the best websites, you have to take a close look at the quality and types of information they provide! 

When it comes to paid homework help services, the prices vary pretty widely depending on the amount of services you want to subscribe to. Subscriptions can cost anywhere from $2 to $150 dollars per month, with the most expensive services offering several hours of one-on-one tutoring with a subject expert per month.

The 5 Best Homework Help Websites 

So, what is the best homework help website you can use? The answer is that it depends on what you need help with. 

The best homework help websites are the ones that are reliable and help you learn the material. They don’t just provide answers to homework questions–they actually help you learn the material. 

That’s why we’ve broken down our favorite websites into categories based on who they’re best for . For instance, the best website for people struggling with math might not work for someone who needs a little extra help with science, and vice versa. 

Keep reading to find the best homework help website for you! 

Best Free Homework Help Site: Khan Academy

  • Price: Free!
  • Best for: Practicing tough material 

Not only is Khan Academy free, but it’s full of information and can be personalized to suit your needs. When you set up your account , you choose which courses you need to study, and Khan Academy sets up a personal dashboard of instructional videos, practice exercises, and quizzes –with both correct and incorrect answer explanations–so you can learn at your own pace. 

As an added bonus, it covers more course topics than many other homework help sites, including several AP classes.

Runner Up: Brainly.com offers a free service that allows you to type in questions and get answers and explanations from experts. The downside is that you’re limited to two answers per question and have to watch ads. 

Best Paid Homework Help Site: Chegg

  • Price: $14.95 to $19.95 per month
  • Best for: 24/7 homework assistance  

This service has three main parts . The first is Chegg Study, which includes textbook solutions, Q&A with subject experts, flashcards, video explanations, a math solver, and writing help. The resources are thorough, and reviewers state that Chegg answers homework questions quickly and accurately no matter when you submit them.  

Chegg also offers textbook rentals for students who need access to textbooks outside of their classroom. Finally, Chegg offers Internship and Career Advice for students who are preparing to graduate and may need a little extra help with the transition out of high school. 

Another great feature Chegg provides is a selection of free articles geared towards helping with general life skills, like coping with stress and saving money. Chegg’s learning modules are comprehensive, and they feature solutions to the problems in tons of different textbooks in a wide variety of subjects. 

Runner Up: Bartleby offers basically the same services as Chegg for $14.99 per month. The reason it didn’t rank as the best is based on customer reviews that say user questions aren’t answered quite as quickly on this site as on Chegg. Otherwise, this is also a solid choice!

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Best Site for Math Homework Help: Photomath

  • Price: Free (or $59.99 per year for premium services) 
  • Best for: Explaining solutions to math problems

This site allows you to t ake a picture of a math problem, and instantly pulls up a step-by-step solution, as well as a detailed explanation of the concept. Photomath also includes animated videos that break down mathematical concepts to help you better understand and remember them. 

The basic service is free, but for an additional fee you can get extra study tools and learn additional strategies for solving common math problems.

Runner Up: KhanAcademy offers in-depth tutorials that cover complex math topics for free, but you won’t get the same tailored help (and answers!) that Photomath offers. 

Best Site for English Homework Help: Princeton Review Academic Tutoring

  • Price: $40 to $153 per month, depending on how many hours of tutoring you want 
  • Best for: Comprehensive and personalized reading and writing help 

While sites like Grammarly and Sparknotes help you by either proofreading what you write via an algorithm or providing book summaries, Princeton Review’s tutors provide in-depth help with vocabulary, literature, essay writing and development, proofreading, and reading comprehension. And unlike other services, you’ll have the chance to work with a real person to get help. 

The best part is that you can get on-demand English (and ESL) tutoring from experts 24/7. That means you can get help whenever you need it, even if you’re pulling an all-nighter! 

This is by far the most expensive homework site on this list, so you’ll need to really think about what you need out of a homework help website before you commit. One added benefit is that the subscription covers over 80 other subjects, including AP classes, which can make it a good value if you need lots of help!  

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Best Site for STEM Homework Help: Studypool

  • Best for: Science homework help
  • Price: Varies; you’ll pay for each question you submit

When it comes to science homework help, there aren’t a ton of great resources out there. The best of the bunch is Studypool, and while it has great reviews, there are some downsides as well. 

Let’s start with the good stuff. Studypool offers an interesting twist on the homework help formula. After you create a free account, you can submit your homework help questions, and tutors will submit bids to answer your questions. You’ll be able to select the tutor–and price point–that works for you, then you’ll pay to have your homework question answered. You can also pay a small fee to access notes, lectures, and other documents that top tutors have uploaded. 

The downside to Studypool is that the pricing is not transparent . There’s no way to plan for how much your homework help will cost, especially if you have lots of questions! Additionally, it’s not clear how tutors are selected, so you’ll need to be cautious when you choose who you’d like to answer your homework questions.  

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What Are the Pros and Cons of Using Homework Help Sites?

Homework help websites can be a great resource if you’re struggling in a subject, or even if you just want to make sure that you’re really learning and understanding topics and ideas that you’re interested in. But, there are some possible drawbacks if you don’t use these sites responsibly. 

We’ll go over the good–and the not-so-good–aspects of getting online homework help below. 

3 Pros of Using Homework Help Websites 

First, let’s take a look at the benefits. 

#1: Better Grades Beyond Homework

This is a big one! Getting outside help with your studies can improve your understanding of concepts that you’re learning, which translates into better grades when you take tests or write essays. 

Remember: homework is designed to help reinforce the concepts you learned in class. If you just get easy answers without learning the material behind the problems, you may not have the tools you need to be successful on your class exams…or even standardized tests you’ll need to take for college. 

#2: Convenience

One of the main reasons that online homework help is appealing is because it’s flexible and convenient. You don’t have to go to a specific tutoring center while they’re open or stay after school to speak with your teacher. Instead, you can access helpful resources wherever you can access the internet, whenever you need them.

This is especially true if you tend to study at off hours because of your extracurriculars, work schedule, or family obligations. Sites that offer 24/7 tutoring can give you the extra help you need if you can’t access the free resources that are available at your school. 

#3: Variety

Not everyone learns the same way. Maybe you’re more of a visual learner, but your teacher mostly does lectures. Or maybe you learn best by listening and taking notes, but you’re expected to learn something just from reading the textbook . 

One of the best things about online homework help is that it comes in a variety of forms. The best homework help sites offer resources for all types of learners, including videos, practice activities, and even one-on-one discussions with real-life experts. 

This variety can also be a good thing if you just don’t really resonate with the way a concept is being explained (looking at you, math textbooks!).

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Not so fast. There are cons to homework help websites, too. Get to know them below!

3 Cons of Using Homework Help Websites 

Now, let’s take a look at the drawbacks of online homework help. 

#1: Unreliable Info

This can be a real problem. In addition to all the really good homework help sites, there are a whole lot of disreputable or unreliable sites out there. The fact of the matter is that some homework help sites don’t necessarily hire people who are experts in the subjects they’re talking about. In those cases, you may not be getting the accurate, up-to-date, and thorough information you need.

Additionally, even the great sites may not be able to answer all of your homework questions. This is especially true if the site uses an algorithm or chatbot to help students…or if you’re enrolled in an advanced or college-level course. In these cases, working with your teacher or school-provided tutors are probably your best option. 

#2: No Clarification

This depends on the service you use, of course. But the majority of them provide free or low-cost help through pre-recorded videos. Watching videos or reading info online can definitely help you with your homework… but you can’t ask questions or get immediate feedback if you need it .

#3: Potential For Scamming 

Like we mentioned earlier, there are a lot of homework help websites out there, and lots of them are scams. The review comments we read covered everything from outdated or wrong information, to misleading claims about the help provided, to not allowing people to cancel their service after signing up. 

No matter which site you choose to use, make sure you research and read reviews before you sign up–especially if it’s a paid service! 

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When Does “Help” Become “Cheating”?

Admittedly, whether using homework help websites constitutes cheating is a bit of a grey area. For instance, is it “help” when a friend reads your essay for history class and corrects your grammar, or is it “cheating”? The truth is, not everyone agrees on when “help” crosses the line into “cheating .” When in doubt, it can be a good idea to check with your teacher to see what they think about a particular type of help you want to get. 

That said, a general rule of thumb to keep in mind is to make sure that the assignment you turn in for credit is authentically yours . It needs to demonstrate your own thoughts and your own current abilities. Remember: the point of every homework assignment is to 1) help you learn something, and 2) show what you’ve learned. 

So if a service answers questions or writes essays for you, there’s a good chance using it constitutes cheating. 

Here’s an example that might help clarify the difference for you. Brainstorming essay ideas with others or looking online for inspiration is “help” as long as you write the essay yourself. Having someone read it and give you feedback about what you need to change is also help, provided you’re the one that makes the changes later. 

But copying all or part of an essay you find online or having someone write (or rewrite) the whole thing for you would be “cheating.” The same is true for other subjects. Ultimately, if you’re not generating your own work or your own answers, it’s probably cheating.

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5 Tips for Finding the Best Homework Help Websites for You

Now that you know some of our favorite homework help websites, free and paid, you can start doing some additional research on your own to decide which services might work best for you! Here are some top tips for choosing a homework help website. 

Tip 1: Decide How You Learn Best 

Before you decide which site or sites you’re going to use for homework help, y ou should figure out what kind of learning style works for you the most. Are you a visual learner? Then choose a site that uses lots of videos to help explain concepts. If you know you learn best by actually doing tasks, choose a site that provides lots of practice exercises.

Tip 2: Determine Which Subjects You Need Help With

Just because a homework help site is good overall doesn’t mean that it’s equally good for every subject. If you only need help in math, choose a site that specializes in that area. But if history is where you’re struggling, a site that specializes in math won’t be much help. So make sure to choose a site that you know provides high-quality help in the areas you need it most. 

Tip 3: Decide How Much One-On-One Help You Need 

This is really about cost-effectiveness. If you learn well on your own by reading and watching videos, a free site like Khan Academy is a good choice. But if you need actual tutoring, or to be able to ask questions and get personalized answers from experts, a paid site that provides that kind of service may be a better option.

Tip 4: Set a Budget

If you decide you want to go with a paid homework help website, set a budget first . The prices for sites vary wildly, and the cost to use them can add up quick. 

Tip 5: Read the Reviews

Finally, it’s always a good idea to read actual reviews written by the people using these homework sites. You’ll learn the good, the bad, and the ugly of what the users’ experiences have been. This is especially true if you intend to subscribe to a paid service. You’ll want to make sure that users think it’s worth the price overall!

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What’s Next?

If you want to get good grades on your homework, it’s a good idea to learn how to tackle it strategically. Our expert tips will help you get the most out of each assignment…and boost your grades in the process.

Doing well on homework assignments is just one part of getting good grades. We’ll teach you everything you need to know about getting great grades in high school in this article.

Of course, test grades can make or break your GPA, too. Here are 17 expert tips that’ll help you get the most out of your study prep before you take an exam.

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Ashley Sufflé Robinson has a Ph.D. in 19th Century English Literature. As a content writer for PrepScholar, Ashley is passionate about giving college-bound students the in-depth information they need to get into the school of their dreams.

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How to use Smodin Omni

1. type your homework question into the search box.

Make your question as precise as possible. The more clearly worded your question is, the more likely Smodin Omni will be able to find the answer to your question.

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Click the search button. Smodin Omni will search our large question-and-answer database as well as the internet for the solution to your question. This typically takes around 10 seconds. We will find relevant internet content, helpful images, and useful explanations.

3. Look for your answer

Majority of common questions are easy to answer, and you will see your answer appear in the answer list. However, more unique questions may not have sufficient answers in our database or on the web.

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Smodin Omni uses various machine learning models to determine the answer to your question. The more questions you ask it, the smarter the Omni becomes. Currently, Smodin Omni can answer a limited amount of question types, but it is growing its understanding of topics daily.

5. Share your answer with your classmates

You love it when your friends help you with your homework, so why not help them with their homework? Share your answers from Smodin Omni to help your classmates with their homework!

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Chemistry Homework Helper

Chemistry Homework Helper

HIX Tutor's AI chemistry homework helper is your go-to companion to master chemistry problem-solving.

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Discover Frequently Asked Chemistry Questions and Their Answers

  • Formula for Cd2+ and PO43- ? also whats its name
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  • Which group contains a chiral carbon? #A.# #"1-bromopropane"#. #B.# #"2-bromopropane"#. #C.# #H_3C−CH_2CHBrCH_2CH_3#. #D.# #"cyclohexyl bromide"#

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Math Solver

Geogebra math solver.

Get accurate solutions and step-by-step explanations for algebra and other math problems, while enhancing your problem-solving skills!

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HungarianAlgorithm.com

Index     Assignment problem     Hungarian algorithm     Solve online    

Solve an assignment problem online

Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.

Fill in the cost matrix ( random cost matrix ):

Don't show the steps of the Hungarian algorithm Maximize the total cost

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Linear Sum Assignment Solver

This section describes the linear sum assignment solver , a specialized solver for the simple assignment problem, which can be faster than either the MIP or CP-SAT solver. However, the MIP and CP-SAT solvers can handle a much wider array of problems, so in most cases they are the best option.

Cost matrix

The costs for workers and task are given in the table below.

Worker Task 0 Task 1 Task 2 Task 3
90 76 75 70
35 85 55 65
125 95 90 105
45 110 95 115

The following sections present a Python program that solves an assignment problem using the linear sum assignment solver.

Import the libraries

The code that imports the required library is shown below.

Define the data

The following code creates the data for the program.

The array is the cost matrix , whose i , j entry is the cost for worker i to perform task j . There are four workers, corresponding to the rows of the matrix, and four tasks, corresponding to the columns.

Create the solver

The program uses the linear assignment solver, a specialized solver for the assignment problem.

The following code creates the solver.

Add the constraints

The following code adds the costs to the solver by looping over workers and tasks.

Invoke the solver

The following code invokes the solver.

Display the results

The following code displays the solution.

The output below shows the optimal assignment of workers to tasks.

The following graph shows the solution as the dashed edges in the graph. The numbers next to the dashed edges are their costs. The total wait time of this assignment is the sum of the costs for the dashed edges, which is 265.

In graph theory, a set of edges in a bipartite graph that matches every node on the left with exactly one node on the right is called a perfect matching .

The entire program

Here is the entire program.

Solution when workers can't perform all tasks

In the previous example, we assumed that all workers can perform all tasks. But this not always the case - a worker might be unable to perform one or more tasks for various reasons. However, it is easy to modify the program above to handle this.

As an example, suppose that worker 0 is unable to perform task 3. To modify the program to take this into account, make the following changes:

  • Change the 0, 3 entry of the cost matrix to the string 'NA' . (Any string will work.) cost = [[90, 76, 75, 'NA'], [35, 85, 55, 65], [125, 95, 90, 105], [45, 110, 95, 115]]
  • In the section of the code that assigns costs to the solver, add the line if cost[worker][task] != 'NA': , as shown below. for worker in range(0, rows): for task in range(0, cols): if cost[worker][task] != 'NA': assignment.AddArcWithCost(worker, task, cost[worker][task]) The added line prevents any edge whose entry in the cost matrix is 'NA' from being added to the solver.

After making these changes and running the modified code, you see the following output:

Notice that the total cost is higher now than it was for the original problem. This is not surprising, since in the original problem the optimal solution assigned worker 0 to task 3, while in the modified problem that assignment is not allowed.

To see what happens if more workers are unable to perform tasks, you can replace more entries of the cost matrix with 'NA' , to denote additional workers who can't perform certain tasks:

When you run the program this time, you get a negative result:

This means there is no way to assign workers to tasks so that each worker performs a different task. You can see why this is so by looking at the graph for the problem (in which there are no edges corresponding to values of 'NA' in the cost matrix).

Since the nodes for the three workers 0, 1, and 2 are only connected to the two nodes for tasks 0 and 1, it not possible to assign distinct tasks to these workers.

The Marriage Theorem

There is a well-known result in graph theory, called The Marriage Theorem , which tells us exactly when you can assign each node on the left to a distinct node on the right, in a bipartite graph like the one above. Such an assignment is called a perfect matching . In a nutshell, the theorem says this is possible if there is no subset of nodes on the left (like the one in the previous example ) whose edges lead to a smaller set of nodes on the right.

More precisely, the theorem says that a bipartite graph has a perfect matching if and only if for any subset S of the nodes on the left side of the graph, the set of nodes on the right side of the graph that are connected by an edge to a node in S is at least as large as S.

Except as otherwise noted, the content of this page is licensed under the Creative Commons Attribution 4.0 License , and code samples are licensed under the Apache 2.0 License . For details, see the Google Developers Site Policies . Java is a registered trademark of Oracle and/or its affiliates.

Last updated 2023-01-18 UTC.

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> Operation Research calculators
AtoZmath.com - Homework help (with all solution steps)
Secondary school, High school and College
Provide step by step solutions of your problems using online calculators (online solvers)
Your textbook, etc
Operation Research Calculators ( )

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1. Processing n Jobs Through 2 Machines Problem
2. Processing n Jobs Through 3 Machines Problem
3. Processing n Jobs Through m Machines Problem
4. Processing 2 Jobs Through m Machines Problem

1. Model-1 : Replacement policy for items whose running cost increases with time and value of money remains constant during a period
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2. : Replacement policy for items whose running cost increases with time but value of money changes constant rate during a period
3. : Group replacement policy
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Operation Research with example
Assignment Problem
1. A department has five employess with five jobs to be permormed. The time (in hours) each men will take to perform each job is given in the effectiveness matrix.
Employees
I II III IV V
Jobs A 10 5 113 15 16
B 3 9 18 13 6
C 10 7 2 2 2
D 7 11 9 7 12
E 7 9 10 4 12
2. In the modification of a plant layout of a factory four new machines M1, M2, M3 and M4 are to be installed in a machine shop. There are five vacant places A, B, C, D and E available. Because of limited space, machine M2 cannot be placed at C and M3 cannot be placed at A. The cost of locating a machine at a place (in hundred rupess) is as follows.
Location
A B C D E
Machine M1 9 11 15 10 11
M2 12 9 -- 10 9
M3 -- 11 14 11 7
M4 14 8 12 7 8





1. A travelling salesman has to visit five cities. He wishes to start from a particular city, visit each city only once and then return to his starting point. The travelling cost of each city from a particular city is given below.
To city
A B C D E
From city A x 2 5 7 1
B 6 x 3 8 2
C 8 7 x 4 7
D 12 4 6 x 5
E 1 3 2 8 x
1. Best-ride airlines that operates seven days a week has the following time-table.
Delhi - Mumbai Mumbai - Delhi
Flight No Departure Arrival
1 7.00 8.00
2 8.00 9.00
3 13.00 14.00
4 18.00 19.00
Flight No Departure Arrival
101 8.00 9.00
102 9.00 10.00
103 12.00 13.00
104 17.00 18.00
Simplex method
Solve the following LP problem by using









1. Use the simplex method to solve the following LP problem.
Maximize Z = 3x1 + 5x2 + 4x3
subject to the constraints
2x1 + 3x2 ≤ 8
2x2 + 5x3 ≤ 10
3x1 + 2x2 + 4x3 ≤ 15
and x1, x2, x3 ≥ 0

2. Use the simplex method to solve the following LP problem.
Maximize Z = 4x1 + 3x2
subject to the constraints
2x1 + x2 ≤ 1000
x1 + x2 ≤ 800
x1 ≤ 400
x2 ≤ 700
and x1, x2 ≥ 0
1. Use the penalty (Big - M) method to solve the following LP problem.
Minimize Z = 5x1 + 3x2
subject to the constraints
2x1 + 4x2 ≤ 12
2x1 + 2x2 = 10
5x1 + 2x2 ≥ 10
and x1, x2 ≥ 0

2. Use the penalty (Big - M) method to solve the following LP problem.
Minimize Z = x1 + 2x2 + 3x3 - x4
subject to the constraints
x1 + 2x2 + 3x3 = 15
2x1 + x2 + 5x3 = 20
x1 + 2x2 + x3 + x4 = 10
and x1, x2, x3, x4 ≥ 0
1. Solve the following LP problem by using the Two-Phase method.
Minimize Z = x1 + x2
subject to the constraints
2x1 + 4x2 ≥ 4
x1 + 7x2 ≥ 7
and x1, x2 ≥ 0

2. Solve the following LP problem by using the Two-Phase method.
Minimize Z = x1 - 2x2 - 3x3
subject to the constraints
-2x1 + 3x2 + 3x3 = 2
2x1 + 3x2 + 4x3 = 1
and x1, x2, x3 ≥ 0
1. Solve the following integer programming problem using Gomory's cutting plane algorithm.
Maximize Z = x1 + x2
subject to the constraints
3x1 + 2x2 ≤ 5
x2 ≤ 2
and x1, x2 ≥ 0 and are integers.

2. Solve the following integer programming problem using Gomory's cutting plane algorithm.
Maximize Z = 2x1 + 20x2 - 10x3
subject to the constraints
2x1 + 20x2 + 4x3 ≤ 15
6x1 + 20x2 + 4x3 ≤ 20
and x1, x2, x3 ≥ 0 and are integers.
1. Use graphical method to solve following LP problem.
Maximize Z = x1 + x2
subject to the constraints
3x1 + 2x2 ≤ 5
x2 ≤ 2
and x1, x2 ≥ 0

2. Use graphical method to solve following LP problem.
Maximize Z = 2x1 + x2
subject to the constraints
x1 + 2x2 ≤ 10
x1 + x2 ≤ 6
x1 - x2 ≤ 2
x1 - 2x2 ≤ 1
and x1, x2 ≥ 0
1. Write the dual to the following LP problem.
Maximize Z = x1 - x2 + 3x3
subject to the constraints
x1 + x2 + x3 ≤ 10
2x1 - x2 - x3 ≤ 2
2x1 - 2x2 - 3x3 ≤ 6
and x1, x2, x3 ≥ 0

2. Write the dual to the following LP problem.
Minimize Z = 3x1 - 2x2 + 4x3
subject to the constraints
3x1 + 5x2 + 4x3 ≥ 7
6x1 + x2 + 3x3 ≥ 4
7x1 - 2x2 - x3 ≤ 10
x1 - 2x2 + 5x3 ≥ 3
4x1 + 7x2 - 2x3 ≥ 2
and x1, x2, x3 ≥ 0
1. Solve the following LP problem by using Branch and Bound method
Max Z = 7x1 + 9x2
subject to
-x1 + 3x2 ≤ 6
7x1 + x2 ≤ 35
x2 ≤ 7
and x1,x2 ≥ 0

2. Solve the following LP problem by using Branch and Bound method
Max Z = 3x1 + 5x2
subject to
2x1 + 4x2 ≤ 25
x1 ≤ 8
2x2 ≤ 10
and x1,x2 ≥ 0

1. Solve LP using zero-one Integer programming problem method
Max Z = 300x1 + 90x2 + 400x3 + 150x4
subject to
35000x1 + 10000x2 + 25000x3 + 90000x4 ≤ 120000
4x1 + 2x2 + 7x3 + 3x4 ≤ 12
x1 + x2 ≤ 1
and x1,x2,x3,x4 ≥ 0

2. Solve LP using 0-1 Integer programming problem method
MAX Z = 650x1 + 700x2 + 225x3 + 250x4
subject to
700x1 + 850x2 + 300x3 + 350x4 ≤ 1200
550x1 + 550x2 + 150x3 + 200x4 ≤ 700
400x1 + 350x2 + 100x3 ≤ 400
x1 + x2 ≥ 1
-x3 + x4 ≤ 1
and x1,x2,x3,x4 ≥ 0
1. Solve the following LP problem by using Revised Simplex method
MAX Z = 3x1 + 5x2
subject to
x1 ≤ 4
x2 ≤ 6
3x1 + 2x2 ≤ 18
and x1,x2 ≥ 0

2. Solve the following LP problem by using Revised Simplex method
MAX Z = 2x1 + x2
subject to
3x1 + 4x2 ≤ 6
6x1 + x2 ≤ 3
and x1,x2 ≥ 0
Transportation Problem using









1. A Company has 3 production facilities S1, S2 and S3 with production capacity of 7, 9 and 18 units (in 100's) per week of a product, respectively. These units are tobe shipped to 4 warehouses D1, D2, D3 and D4 with requirement of 5,6,7 and 14 units (in 100's) per week, respectively. The transportation costs (in rupees) per unit between factories to warehouses are given in the table below.
D D D D Capacity
S 19 30 50 10 7
S 70 30 40 60 9
S 40 8 70 20 18
Demand 5 8 7 14 34
D D D D Supply
S 11 13 17 14 250
S 16 18 14 10 300
S 21 24 13 10 400
Demand 200 225 275 250
3. A company has factories at F1, F2 and F3 which supply to warehouses at W1, W2 and W3. Weekly factory capacities are 200, 160 and 90 units, respectively. Weekly warehouse requiremnet are 180, 120 and 150 units, respectively. Unit shipping costs (in rupess) are as follows:
W W W Supply
F 16 20 12 200
F 14 8 18 160
F 26 24 16 90
Demand 180 120 150 450
P Q R S Supply
A 6 3 5 4 22
B 5 9 2 7 15
C 5 7 8 6 8
Demand 7 12 17 9 45
4.
1. An assembly is to be made from two parts X and Y. Both parts must be turned on a lathe Y must be polished where as X need not be polished. The sequence of acitivities, together with their predecessors, is given below
Activity Description Predecessor Activity
A Open work order -
B Get material for X A
C Get material for Y A
D Turn X on lathe B
E Turn Y on lathe B,C
F Polish Y E
G Assemble X and Y D,F
H Pack G
2. An established company has decided to add a new product to its line. It will buy the product from a manufacturing concern, package it, and sell it to a number of distributors that have been selected on a geographical basis. Market research has already indicated the volume expected and the size of sales force required. The steps shown in the following table are to be planned.
Activity Description Predecessor Activity Duration (days)
A Organize sales office - 6
B Hire salesman A 4
C Train salesman B 7
D Select advertising agency A 2
E Plan advertising campaign D 4
F Conduct advertising campaign E 10
G Design package - 2
H Setup packaging campaign G 10
I Package initial stocks J,H 6
J Order stock from manufacturer - 13
K Select distributors A 9
L Sell to distributors C,K 3
M Ship stocks to distributors I,L 5
5.
1. There are seven jobs, each of which has to go through the machines A and B in the order AB. Processing times in hours are as follows.
Job 1 2 3 4 5 6 7
Machine A 3 12 15 6 10 11 9
Machine B 8 10 10 6 12 1 3
2. Find the sequence that minimizes the total time required in performing the following job on three machines in the order ABC. Processing times (in hours) are given in the following table.
Job 1 2 3 4 5
Machine A 8 10 6 7 11
Machine B 5 6 2 3 4
Machine C 4 9 8 6 5
6.
1. A firm is considering the replacement of a machine, whose cost price is Rs 12,200 and its scrap value is Rs 200. From experience the running (maintenance and operating) costs are found to be as follows:
Year12345678
Running Cost2005008001,2001,8002,5003,2004,000
1. The data collected in running a machine, the cost of which is Rs 60,000 are given below:
Year12345
Resale Value42,00030,00020,40014,4009,650
Cost of spares4,0004,2704,8805,7006,800
Cost of labour14,00016,00018,00021,00025,000
1. Machine A costs Rs 45,000 and its operating costs are estimated to be Rs 1,000 for the first year increasing by Rs 10,000 per year in the second and subsequent years. Machine B costs Rs 50,000 and operating costs are Rs 2,000 for the first year, increasing by Rs 4,000 in the second and subsequent years. If at present we have a machine of type A, should we replace it with B? if so when? Assume that both machines have no resale value and their future costs are not discounted.

Replacement policy for items whose running cost increases with time but value of money changes constant rate during a period
1. An engineering company is offered a material handling equipment A. It is priced at Rs 60,000 includeing cost of installation. The costs for operation and maintenance are estimated to be Rs 10,000 for each of the first five years, increasing every year by Rs 3,000 in the sixth and subsequent years. The company expects a return of 10 percent on all its investment. What is the optimal replacement period?
Year1234567
Running Cost10,00010,00010,00010,00010,00013,00016,000

Group replacement policy
1. A computer contains 10,000 resistors. When any resistor fails, it is replaced. The cost of replacing a resistor individually is Rs 1 only. If all the resistors are replaced at the same time, the cost per resistor would be reduced to 35 paise. The percentage of surviving resistors say S(t) at the end of month t and the probability of failure P(t) during the month t are as follows:
t0123456
P(t)00.030.070.200.400.150.15
t012345
P(t)00.050.100.200.400.25











1. For the game with payoff matrix
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` -1  2  -2 
`A_2` 6  4  -6 
1. Dominance Example
Player `B`
`B_1``B_2``B_3``B_4`
Player `A``A_1` 3  5  4  2 
`A_2` 5  6  2  4 
`A_3` 2  1  4  0 
`A_4` 3  3  5  2 
1. Find the solution of game using algebraic method for the following pay-off matrix
Player `B`
`B_1``B_2`
Player `A``A_1` 1  7 
`A_2` 6  2 
1. Find the solution of game using calculus method for the following pay-off matrix
Player `B`
`B_1``B_2`
Player `A``A_1` 1  3 
`A_2` 5  2 
1. Find the solution of game using arithmetic method for the following pay-off matrix
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 10  5  -2 
`A_2` 13  12  15 
`A_3` 16  14  10 
1. Find the solution of game using matrix method for the following pay-off matrix
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 1  7  2 
`A_2` 6  2  7 
`A_3` 5  1  6 
1. Find the solution of game using 2Xn Games method for the following pay-off matrix
Player `B`
`B_1``B_2`
Player `A``A_1` -3  4 
`A_2` -1  1 
`A_3` 7  -2 
1. Find the solution of game using graphical method method for the following pay-off matrix
Player `B`
`B_1``B_2`
Player `A``A_1` 1  -3 
`A_2` 3  5 
`A_3` -1  6 
`A_4` 4  1 
`A_5` 2  2 
`A_6` -5  0 
1. Find the solution of game using linear programming method for the following pay-off matrix
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 3  -4  2 
`A_2` 1  -7  -3 
`A_3` -2  4  7 

online assignment solver

online assignment solver

Grade Calculator

Grade Calculator

Grade Calculator

  • Grade calculator
  • Final grade calculator
  • GPA calculator
AssessmentGrade (%)Grade (points)Grade (letter)WeightWeightMax Grade

Understanding how to calculate your current grade in a course is advantageous for planning what you need to achieve your goal’s overall course grade. The following Grade Calculator serves as an easy-to-use helpful tool to calculate your current grade of the course before the final examination.  

What is a Grade Calculator?  

A Grade Calculator is a free online tool designed to help students and educators determine academic grades based on entered scores and weights. It simplifies the process of calculating current grades, helping users navigate their academic journeys.   

The Grade Calculator helps students estimate the impact of each assignment on their course’s weighted average grade. That means the overall grade of a course depends on 2 main factors: the grade of each assignment (g) and the corresponding weight of each assignment (w).  

A Grade calculator helps you find your current average score in a course based on completed assignments up to the current point in the semester. The Final grade calculator then calculates the score you need to achieve in your remaining assignment (the final exam) to reach your desired grade of the course

How to Use a Grade Calculator?  

Using a Grade Calculator is a straightforward process that involves entering relevant information about your academic performance. To utilize this calculator, input your current percentage for each assignment, test, or exam, along with its respective weight towards your final grade. For each additional assignment, test, or exam, click on "Add Assignment." Your results will automatically update as you input each component , allowing you to track your progress throughout the course.  

Here's a step-by-step guide on how to use a Grade Calculator:  

Step 1: Input the Assignments.  

Users manually enter the name of each assignment, for example: Assignment 1, 2, 3, Homework, Final Exam, etc.  

Step 2: Input the grade.  

Enter their scores for each assignment, test, project, or other exam throughout the course. Each entry typically includes the earned percentage (10%, 30%, 50%, etc.), letter (A+, B-, D, etc.), or points (20, 50, 175, etc.).  

Step 3: Input the weight.  

Enter the weight of that assignment into the overall course grade. The weight indicates that different assignments may have varying impacts on the final grade. A final exam might have a higher weight than a small task.  

Step 4: Calculate the grade automatically.  

The tool then automatically calculates the cumulative grade based on the entered grades and weights. Users can see their current grade as well as how each assignment contributes to the overall grade.  

Step 5: Adjust as needed.  

Users can adjust grades or weights to see how changes impact the overall course performance. This dynamic feature allows for real-time exploration of different scenarios, helping users make informed decisions about their academic strategy and goal achievement.  

Weighted Grade Calculation: Formula and Example  

The calculation of a weighted grade involves summing the products of the weights (w) and the corresponding grades (g).  

Weighted Grade = (w₁ × g₁ + w₂ × g₂ + w₃ × g₃ + …) / (g₁ + g₂ + g₃ +...)  

Example 1: Grade type: Percentage  

Determine the weighted grade of a course, in which:  

  • Assignment with a grade (percentage) of 80 and a weight of 30.  
  • Homework with a grade (percentage) of 90 and a weight of 20.  
  • Final exam with a grade (percentage) of 72 and a weight of 50.  

The weighted average grade is determined by the formula:  

Weighted Grade = (w₁ × g₁ + w₂ × g₂ + w₃ × g₃ + …) / (w₁ + w₂ + w₃+...)  

Substituting the values:  

Weighted Grade = (30 × 80 + 20 × 90 + 50 × 72) / (30 + 20 + 50) = 78  

Example 2: Grade type: Letter  

  • Assignment 1 with a grade (letter) of A+ and a weight of 20.  
  • Assignment 2 with a grade (letter) of B and a weight of 20.  
  • Final exam with a grade (letter) of C- and a weight of 60.  

The weighted average grade of the course is calculated by the formula:

Weighted Grade = (w₁ × g₁ + w₂ × g₂ + w₃ × g₃ + …) / (w₁ + w₂ + w₃ +...)  

Weighted Grade = (20 × 4.33 + 20 × 3.00 + 60 × 1.67) / (20 + 20 + 60) = 2.64   

The table below shows how your letter grades convert to a numeric grade (4.0 scale) and percentage grade (% scale):  

 

 

 

A+ 

4.33 - above 

97 - above 

A 

4.00 - 4.32 

93 - 96,99 

A- 

3.67 - 3.99 

90 - 92,99 

B+ 

3.33 - 3.66 

87 - 89,99 

B 

3.00 - 3.32 

83 - 87,99 

B- 

2.67 - 2.99 

80 - 82,99 

C+ 

2.33 - 2.66 

77 - 79,99 

C 

2.00 - 2.32 

73 - 76,99 

C- 

1.67 - 1.99 

70 - 72,99 

D+ 

1.33 - 1.66 

67 - 69,99 

D 

1.00 - 1.32 

63 - 66,99 

D- 

0.67 - 0.99 

60 - 62,99 

F 

0.00 - 0.66 

0 - 59,99 

Example 3: Grade type: Point  

Consider the following case:  

  • For Assignment 1, the grade is 60 out of 80.  
  • For Assignment 2, the grade is 30 out of 50.  
  • For Homework, the grade is 120 out of 120.  
  • For the Final exam, the grade is 60 out of 100.  

The formula to calculate the weighted average grade is:  

Weighted Grade = sum of real grade / sum of maximum grade  

Weighted Grade = (60 + 30 + 120 + 60) / (80 + 50 + 120 + 100) = 77.14  

Important Role of the Grade Calculator in Academic Path  

The Grade Calculator functions as a flexible tool that aids both educators and students, fostering efficiency and transparency. Knowing the average grade is essential for strategic decision-making in scenarios and setting achievable academic goals.  

Scenario Planning:  

Some Grade Calculators allow users to experiment with different scenarios. For instance, students can input hypothetical scores for future assignments or exams to see how they would impact their final grade. This helps in understanding how adjustments to upcoming assessments may impact the overall class performance.  

Teachers can use a Grade Calculator to streamline the grading process. By inputting scores and weights, the tool can quickly calculate overall grades, saving time and ensuring accuracy.  

Goal Setting:    

Users can set grade goals and determine the scores needed on upcoming assessments to achieve those goals. This application is particularly helpful for students who aim for a specific final course grade. Goal-setting helps students set realistic academic goals and understand the scores needed to achieve them. Knowing their current grade and having the ability to plan for future assessments can reduce stress for students.  

The Grade calculator provides the average score for a specific course. Students can use this result to calculate their GPA, which represents the average score across all their courses. In essence, the output from the Grade calculator acts as the input for the GPA calculator.

3 Outstanding Features of Grade Calculator  

Using our Grade Calculator is simple and straightforward, even if you are a first-time user. The Grade Calculator is crafted with the user in mind, offering many noticeable benefits:  

Customizable by Adding or Subtracting Assignments  

Recognizing the diversity of grading systems in different educational institutions, the tool offers customization options. Users have the flexibility to tailor the tool to their specific needs. For example, users can add as many assignments as they want, and adjust the weight to align with their school's unique grading system.  

Compatible with Multiple Devices  

The tool is accessible across various platforms to accommodate different user preferences and device types. It is available as both a web application and a mobile app. Users can access it conveniently from desktops, laptops, tablets, and smartphones.  

Easy-to-Understand and Easy-to-Use Interface  

The user interface is designed to be intuitive and user-friendly, prioritizing ease of use. Input fields are labeled logically, ensuring users can easily understand and input the required information. The overall design focuses on simplicity enhancing the overall user experience.  

To sum up, the Grade Calculator is considered a trusted tool for students and educators alike on their academic journeys. Its friendly interface and accurate calculations make it a valuable companion, helping everyone calculate the grade of the course effectively.  

Grade Calculator - FAQs  

What grade do i need to pass a college class  .

The grade needed to pass a college class varies depending on the grading system used by the schools, colleges, and academic institutions . In many cases, a passing grade is a D or higher, which is usually equivalent to a numerical grade of 60% or more. However, some programs or courses may require a higher minimum passing grade, so it's important to check your college's policies.  

How do you calculate the percentage grade?  

To calculate a percentage grade, you divide the points earned by the total points possible and then multiply by 100. For example, if you earned 85 points out of a possible 100, your percentage grade would be: (85/100) * 100 = 85%.  

How much will a 0 affect my grade?  

A zero can significantly impact your grade, especially if it's for a major assignment or test. Since a zero has a large weight in the calculation of your average score, it can pull down your overall grade significantly.  

How much will a 71 affect my grade?  

The impact of a 71 on your grade depends on several factors, such as the weight of the assignment or test in the overall course grade and the grading scale used by your instructor. If the 71 is for a major assignment or test and carries a significant weight in the course, it could have a noticeable effect on your overall grade, potentially lowering it. However, if the assignment is one of many and has a lower weight in the course, its impact may be less significant.

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Grade Calculator

Use this calculator to find out the grade of a course based on weighted averages. This calculator accepts both numerical as well as letter grades. It also can calculate the grade needed for the remaining assignments in order to get a desired grade for an ongoing course.


(optional)
Final Grade Goal
Weight of Remaining Tasks

online assignment solver

Grade Format: Points, percentage, mix Letters
Weight Format: Percentage Points
Show Final Grade Planning Options
 

Final Grade Calculator

Use this calculator to find out the grade needed on the final exam in order to get a desired grade in a course. It accepts letter grades, percentage grades, and other numerical inputs.

Related GPA Calculator

The calculators above use the following letter grades and their typical corresponding numerical equivalents based on grade points.

Letter GradeGPAPercentage
A+4.397-100%
A493-96%
A-3.790-92%
B+3.387-89%
B383-86%
B-2.780-82%
C+2.377-79%
C273-76%
C-1.770-72%
D+1.367-69%
D163-66%
D-0.760-62%
F00-59%

Brief history of different grading systems

In 1785, students at Yale were ranked based on "optimi" being the highest rank, followed by second optimi, inferiore (lower), and pejores (worse). At William and Mary, students were ranked as either No. 1, or No. 2, where No. 1 represented students that were first in their class, while No. 2 represented those who were "orderly, correct and attentive." Meanwhile at Harvard, students were graded based on a numerical system from 1-200 (except for math and philosophy where 1-100 was used). Later, shortly after 1883, Harvard used a system of "Classes" where students were either Class I, II, III, IV, or V, with V representing a failing grade. All of these examples show the subjective, arbitrary, and inconsistent nature with which different institutions graded their students, demonstrating the need for a more standardized, albeit equally arbitrary grading system.

In 1887, Mount Holyoke College became the first college to use letter grades similar to those commonly used today. The college used a grading scale with the letters A, B, C, D, and E, where E represented a failing grade. This grading system however, was far stricter than those commonly used today, with a failing grade being defined as anything below 75%. The college later re-defined their grading system, adding the letter F for a failing grade (still below 75%). This system of using a letter grading scale became increasingly popular within colleges and high schools, eventually leading to the letter grading systems typically used today. However, there is still significant variation regarding what may constitute an A, or whether a system uses plusses or minuses (i.e. A+ or B-), among other differences.

An alternative to the letter grading system

Letter grades provide an easy means to generalize a student's performance. They can be more effective than qualitative evaluations in situations where "right" or "wrong" answers can be easily quantified, such as an algebra exam, but alone may not provide a student with enough feedback in regards to an assessment like a written paper (which is much more subjective).

Although a written analysis of each individual student's work may be a more effective form of feedback, there exists the argument that students and parents are unlikely to read the feedback, and that teachers do not have the time to write such an analysis. There is precedence for this type of evaluation system however, in Saint Ann's School in New York City, an arts-oriented private school that does not have a letter grading system. Instead, teachers write anecdotal reports for each student. This method of evaluation focuses on promoting learning and improvement, rather than the pursuit of a certain letter grade in a course. For better or for worse however, these types of programs constitute a minority in the United States, and though the experience may be better for the student, most institutions still use a fairly standard letter grading system that students will have to adjust to. The time investment that this type of evaluation method requires of teachers/professors is likely not viable on university campuses with hundreds of students per course. As such, although there are other high schools such as Sanborn High School that approach grading in a more qualitative way, it remains to be seen whether such grading methods can be scalable. Until then, more generalized forms of grading like the letter grading system are unlikely to be entirely replaced. However, many educators already try to create an environment that limits the role that grades play in motivating students. One could argue that a combination of these two systems would likely be the most realistic, and effective way to provide a more standardized evaluation of students, while promoting learning.

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