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Thread: Wrong number of arguments or invalid property assignments inserting a hyperlink

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Wrong number of arguments or invalid property assignments inserting a hyperlink

Hi all, please can someone give me a pointer, I'm self taught and usually scour forums to help me find answers to get my code to work but in this case I'm struggling. Everything I read says the code below should work but.... I'm using Excel to open word and generate a document from a series of strings stored in the excel file. One of my strings needs to have a hyperlink added. So I set the display text as disp from a value from excel. I then generate the hyperlink string by concatenating 2 fields as hyperadd (i'ts quite long). I then search for a bookmark "law" and select the 8 character word straight after it. Then I try to add the hyperlink at the selected txt and get "Wrong number of arguments or invalid property assignments". Any ideas? (bound to be something simple!) I suspect the issue is with the .range (and it not recognising my selection from the previous row but.....) Thanks If fieldtopass = "X9_0CX" Then Let disp = valuetopass If fieldtopass = "X9_0DX" Then Let hyperadd = valuetopass If fieldtopass = "X9_0EX" Then Let hyperadd = hyperadd & valuetopass With wrdDoc .Bookmarks("law").Select .Application.Selection.MoveRight Unit:=wdCharacter, Count:=8, Extend:=wdExtend .Application.Selection.Hyperlinks.Add Anchor:=Selection.Range, Address:=hyperadd, TextToDisplay:=disp End With End If
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The following works fine from within Word: Sub Test() Dim wrdDoc As Document Dim hyperadd As String, disp As String Set wrdDoc = ActiveDocument hyperadd = " www.google.com " disp = "Google" With wrdDoc .Bookmarks("law").Select Application.Selection.MoveRight Unit:=wdCharacter, Count:=8, Extend:=wdExtend Application.Selection.Hyperlinks.Add Anchor:=Selection.Range, Address:=hyperadd, TextToDisplay:=disp End With End Sub I suspect that you use of "Application" is referencing Excel and not Word. I don't have time to test in an Excel environment right now, but try replacing .Application with .Parent.
Greg Visit my website: http://gregmaxey.com
Hi Greg, yes I'm calling word from excel. I have tried .parent and it throws the same error. Thanks
Either of the following work calling Word from Excel. The issue is you are trying to use the Excel Application (and the Excel Selection) in a Word process: Option Explicit Sub ScratchMacroI() 'A basic Word macro coded by Greg Maxey, http://gregmaxey.com/word_tips.html , 9/17/2018 Dim oApp As Object Dim oDoc As Object Dim hyperadd As String, disp As String hyperadd = " www.google.com " disp = "Google" Set oApp = CreateObject("Word.Application") Set oDoc = oApp.Documents.Open("D:\Text.docx") With oDoc .Bookmarks("law").Select .Parent.Selection.MoveRight Unit:=1, Count:=8, Extend:=1 .Parent.Selection.Hyperlinks.Add Anchor:=.Parent.Selection.Range, Address:=hyperadd, TextToDisplay:=disp .Close -1 End With oApp.Quit Set oApp = Nothing lbl_Exit: Exit Sub End Sub Sub ScratchMacroII() 'A basic Word macro coded by Greg Maxey, http://gregmaxey.com/word_tips.html , 9/17/2018 Dim oApp As Object Dim oDoc As Object Dim hyperadd As String, disp As String hyperadd = " www.google.com " disp = "Google" Set oApp = CreateObject("Word.Application") Set oDoc = oApp.Documents.Open("D:\Text.docx") oDoc.Bookmarks("law").Select oApp.Selection.MoveRight Unit:=1, Count:=8, Extend:=1 oApp.Selection.Hyperlinks.Add Anchor:=oApp.Selection.Range, Address:=hyperadd, TextToDisplay:=disp oDoc.Close -1 oApp.Quit Set oApp = Nothing lbl_Exit: Exit Sub End Sub
Thanks Greg that worked, I just inserted " Add Anchor:=.Application.Selection.Range" into my code.
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Wrong number of Arguments or Invalid property assignment

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vba wrong number of arguments or invalid property assignment dictionary

Hello - great tips on this website - giving me some great ideas - dont know whether I use them right yet - still knew to this. Below is my macro for taking a range of data in two columns, pivoting it, and replacing the original data with the pivoted data. I have had this working fine in a simpler form - but I am at present improving it to work on a variable data range!! Problem I have atm is that I get a "Wrong number of Arguments or Invalid property assignment" compile error whereas the same code previously worked fine - any ideaS?????? i have pointed out the point below where the problem starts!!! Sub Pivot_V5() ' ' Pivot_V5 Macro ' Macro recorded 17/07/2005 by Greg Sheriston ' ' ActiveWorkbook.Names.Add Name:="List", RefersToR1C1:= _ "=OFFSET(Sheet3!R1C1,4,0,COUNTA(Sheet3!C1),2)" ActiveWorkbook.Names.Add Name:="List2", RefersToR1C1:= _ "=OFFSET(Sheet3!R1C1,5,0,COUNTA(Sheet3!C1),2)" ActiveWorkbook.PivotCaches.Add(SourceType:=xlDatabase, SourceData:="List"). _ CreatePivotTable TableDestination:="'[Pivot test.xls]Sheet3'!R6C5", _ TableName:="PivotTable3", DefaultVersion:=xlPivotTableVersion10 ActiveSheet.PivotTables("PivotTable3").AddFields RowFields:="Stk no" ActiveSheet.PivotTables("PivotTable3").PivotFields("Val").Orientation = _ xlDataField ActiveWorkbook.ShowPivotTableFieldList = True Application.CommandBars("PivotTable").Visible = False ActiveWorkbook.ShowPivotTableFieldList = False Range("List2").Select <-----THIS BIT Range(Selection, Selection.End(xlDown)).Select Selection.ClearContents Range("E8:F8").Select Range(Selection, Selection.End(xlDown)).Select Range("E8:F32").Select Selection.Copy Range("A6").Select ActiveSheet.Paste Application.CutCopyMode = False Selection.Sort Key1:=Range("B6"), Order1:=xlAscending, Header:=xlNo, _ OrderCustom:=1, MatchCase:=False, Orientation:=xlTopToBottom, _ DataOption1:=xlSortNormal Selection.Borders(xlDiagonalDown).LineStyle = xlNone Selection.Borders(xlDiagonalUp).LineStyle = xlNone Selection.Borders(xlEdgeLeft).LineStyle = xlNone Selection.Borders(xlEdgeTop).LineStyle = xlNone Selection.Borders(xlEdgeBottom).LineStyle = xlNone Selection.Borders(xlEdgeRight).LineStyle = xlNone Selection.Borders(xlInsideVertical).LineStyle = xlNone Selection.Borders(xlInsideHorizontal).LineStyle = xlNone Selection.NumberFormat = "#,##0.00_ ;[Red]-#,##0.00 " Columns("E:F").Select Selection.Delete Shift:=xlToLeft Range("A1").Select End Sub ANY ideas greatly appreciated - thanks in advance Greg

Re: Wrong number of Arguments or Invalid property assignment

Try Application.Goto Reference:="List2" -- Greetings from New Zealand Bill K "Turin" < [email protected] > wrote in message news: [email protected] ... > > Hello - great tips on this website - giving me some great ideas - dont > know whether I use them right yet - still knew to this. > > Below is my macro for taking a range of data in two columns, pivoting > it, and replacing the original data with the pivoted data. I have had > this working fine in a simpler form - but I am at present improving it > to work on a variable data range!! > > Problem I have atm is that I get a "Wrong number of Arguments or > Invalid property assignment" compile error whereas the same code > previously worked fine - any ideaS?????? i have pointed out the point > below where the problem starts!!! > > > Sub Pivot_V5() > ' > ' Pivot_V5 Macro > ' Macro recorded 17/07/2005 by Greg Sheriston > ' > > ' > ActiveWorkbook.Names.Add Name:="List", RefersToR1C1:= _ > "=OFFSET(Sheet3!R1C1,4,0,COUNTA(Sheet3!C1),2)" > > ActiveWorkbook.Names.Add Name:="List2", RefersToR1C1:= _ > "=OFFSET(Sheet3!R1C1,5,0,COUNTA(Sheet3!C1),2)" > > ActiveWorkbook.PivotCaches.Add(SourceType:=xlDatabase, > SourceData:="List"). _ > CreatePivotTable TableDestination:="'[Pivot > test.xls]Sheet3'!R6C5", _ > TableName:="PivotTable3", > DefaultVersion:=xlPivotTableVersion10 > ActiveSheet.PivotTables("PivotTable3").AddFields RowFields:="Stk > no" > > ActiveSheet.PivotTables("PivotTable3").PivotFields("Val").Orientation = > _ > xlDataField > ActiveWorkbook.ShowPivotTableFieldList = True > Application.CommandBars("PivotTable").Visible = False > ActiveWorkbook.ShowPivotTableFieldList = False > > > > Range("List2").Select <-----THIS BIT > Range(Selection, Selection.End(xlDown)).Select > Selection.ClearContents > > > > Range("E8:F8").Select > Range(Selection, Selection.End(xlDown)).Select > Range("E8:F32").Select > Selection.Copy > > > Range("A6").Select > ActiveSheet.Paste > Application.CutCopyMode = False > Selection.Sort Key1:=Range("B6"), Order1:=xlAscending, > Header:=xlNo, _ > OrderCustom:=1, MatchCase:=False, Orientation:=xlTopToBottom, > _ > DataOption1:=xlSortNormal > Selection.Borders(xlDiagonalDown).LineStyle = xlNone > Selection.Borders(xlDiagonalUp).LineStyle = xlNone > Selection.Borders(xlEdgeLeft).LineStyle = xlNone > Selection.Borders(xlEdgeTop).LineStyle = xlNone > Selection.Borders(xlEdgeBottom).LineStyle = xlNone > Selection.Borders(xlEdgeRight).LineStyle = xlNone > Selection.Borders(xlInsideVertical).LineStyle = xlNone > Selection.Borders(xlInsideHorizontal).LineStyle = xlNone > Selection.NumberFormat = "#,##0.00_ ;[Red]-#,##0.00 " > Columns("E:F").Select > Selection.Delete Shift:=xlToLeft > > > > Range("A1").Select > End Sub > > > ANY ideas greatly appreciated - thanks in advance Greg > > > -- > Turin > ------------------------------------------------------------------------ > Turin's Profile: > http://www.excelforum.com/member.php...o&userid=24987 > View this thread: http://www.excelforum.com/showthread...hreadid=387864 >

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Debug wrong number of arguments or invalid property assignment error.

  • Thread starter Harshil Mehta
  • Start date Oct 6, 2020
  • Tags #excel #vba

Harshil Mehta

Board regular.

  • Oct 6, 2020

I have 7 sheets in total and want to make save as for the first 5 sheets with time stamp and password. The below code gives an error msg "wrong number of arguments or invalid property assignment" highlighting the word FORMAT. This code used to work perfectly before adding the the 7th sheet. The 7th sheet is a place where Raw Data is dumped and with the help of the VBA Code the data is populated into different sheets. Could anyone please help me? VBA Code: Sub Make_SaveAs() Dim ArrayOne() As String Dim Mypassword As String Application.ScreenUpdating = False Mypassword = Sheets(6).Range("E2") ReDim ArrayOne(1 To 5) For i = 1 To 5 ArrayOne(i) = Sheets(i).Name Next Worksheets(ArrayOne()).Copy With ActiveWorkbook .SaveAs Filename:=Environ("USERPROFILE") & "\Desktop\" & Format(Now(), "YYYYMMDD -") & " Client Design - " & ThisWorkbook.Sheets(6).Range("D2") & "_" & ThisWorkbook.Sheets(6).Range("C2") & ".xlsb", FileFormat:=xlExcel12, Password:=Mypassword .Close SaveChanges:=False End With Application.ScreenUpdating = True MsgBox "File Saved on Deskstop" End Sub  

Excel Facts

davesexcel

Well-known Member

Is it possible your desktop is connect to OneDrive? Look at the differences between these two msgboxes. VBA Code: MsgBox Environ("USERPROFILE") & "\Desktop\" MsgBox CreateObject("WScript.Shell").specialfolders("Desktop") & "\"  

davesexcel said: Is it possible your desktop is connect to OneDrive? Look at the differences between these two msgboxes. VBA Code: MsgBox Environ("USERPROFILE") & "\Desktop\" MsgBox CreateObject("WScript.Shell").specialfolders("Desktop") & "\" Click to expand...

So was there a difference in the msgboxes? Step through the code and see if the string variables do not contain illegal characters. VBA Code: Sub Make_SaveAs() Dim ArrayOne() As String Dim Mypassword As String Dim dr As String, dt As String, nm As String, fBM As String Dim sh As Worksheet Set WS = Sheet6 dr = CreateObject("WScript.Shell").specialfolders("Desktop") & "\" 'dr = "C:\Users\davem\OneDrive\Desktop\" dt = "Client Design - " & Format(Now(), "YYYYMMDD -") nm = WS.Range("D2").Value & "_" & WS.Range("C2").Value & ".xlsb" FNM = dr & dt & nm Application.ScreenUpdating = False Mypassword = WS.Range("E2") ReDim ArrayOne(1 To 5) For i = 1 To 5 ArrayOne(i) = Sheets(i).Name Next Worksheets(ArrayOne()).Copy With ActiveWorkbook .SaveAs Filename:=dr & dt & nm, FileFormat:=xlExcel12 ', Password:=Mypassword .Close SaveChanges:=False End With Application.ScreenUpdating = True MsgBox "File Saved on Deskstop" End Sub  

davesexcel said: So was there a difference in the msgboxes? Click to expand...

vba wrong number of arguments or invalid property assignment dictionary

Okay. I was not getting a format error.  

davesexcel said: Okay. I was not getting a format error. Click to expand...

RoryA

MrExcel MVP, Moderator

It sounds like you created a routine/variable called Format.  

Fluff

Make sure that you do not have subs, functions or variables called Format  

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